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3 years ago

Three consecutive numbers added form 69. What is the third number?

1 answer:

8 0

SOLUTION:

Let third number of three numbers = x

x + x - 1 + x - 2 = 69

3x - 3 = 69

3x = 69 + 3

3x = 72

x = 72 / 3

x = 24

FINAL ANSWER:

Therefore, the third number is 24.

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To win a prize in a game, a player must throw a ball into a

Georgia [21]

Answer:

0.50

Step-by-step explanation:

0.30 + 0.20 = 0.50

(That answer feels almost too easy so I am not positive. I would wait for other answers to come in before submitting for your quiz/homework)

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4 years ago

Diego eats 1/5 of a loaf of bread each day. On Tuesday, Diego eats 1/4 of the day’s portion before lunch. What fraction of the w

LiRa [457]

Answer:

$\frac{1}{20}$

Step-by-step explanation:

We have been given that Diego eats 1/5 of a loaf of bread each day. On Tuesday, Diego eats 1/4 of the day’s portion before lunch.

To find the fraction of the whole loaf eaten by Diego before lunch on Tuesday, we will find 1/4 of 1/5 as:

$\text{Fraction of the whole loaf eaten by Diego}=\frac{1}{5}\times \frac{1}{4}$

$\text{Fraction of the whole loaf eaten by Diego}=\frac{1\times1}{5\times4}$

$\text{Fraction of the whole loaf eaten by Diego}=\frac{1}{20}$

Therefore, Diego has eaten $\frac{1}{20}$ of the whole loaf before lunch on Tuesday.

4 0

3 years ago

For each carbon-14 atom, there are approximately 10^12 carbon-12 atoms. This ratio is constant in each organism. The carbon-12 r

Bond [772]

Answer:

1) There are 100 carbon-14 atoms in the wood when it died

2) A function that models the number 'N' of carbon-14 atoms present in the wood (t) years after it died is presented as follows;

$N = 100 \times \left (\dfrac{1}{2} \right )^{\dfrac{t}{5,730} }$

Step-by-step explanation:

The given parameters are;

The number of carbon-12 for each carbon-14 atom ≈ 10¹² carbon-12 atoms

The number of carbon-12 in the piece of wood = 10¹⁴ carbon-12 atoms

The number of carbon-14 in the piece of wood = 40 carbon-14 atoms

The number of carbon-12 in an organism = Constant

The number of carbon-14 in an organism = Decays

1) Given that the number of carbon-12 in an organism is constant, and there are 10¹² carbon-12 atoms per each carbon-14 atom, therefore, we have;

The number of carbon-12 atoms in the wood when it died = 10¹⁴ carbon-12 atoms

The number of carbon-14 atoms in the wood when it died = (10¹⁴ carbon-12 atoms)/(10¹² carbon-12 atoms/(carbon-14 atom)) = 100 carbon-14 atoms

The number of carbon-14 atoms in the wood when it died = 100 carbon-14 atoms

2) The half life of a radioactive isotope is given by the following formula;

$N(t) = N_0 \cdot \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{\frac{1}{2} }} }$

The half life of carbon-14 atoms, $t_{\frac{1}{2} }$ ≈ 5,730 years

N₀ = The amount of carbon-14 present in the wood when it died = 100 carbon-14 atoms

Therefore, we have;

The number, N, of carbon-14 atoms present in the wood (t) years after it died is given as follows;

$N = 100 \times \left (\dfrac{1}{2} \right )^{\dfrac{t}{5,730} }$

3 0

3 years ago

Help please!! will give brainlest

Dmitry [639]

Answer:

Step-by-step explanation:

8 0

3 years ago

Can someone help me with this question?

belka [17]

Answer:

The required probability is 0.0155.

Step-by-step explanation:

We are given that the one-year survival rate for pancreatic cancer is 20%.

Of 12 people diagnosed with pancreatic cancer at one hospital, 6 survived one year.

The above situation can be represented through binomial distribution;

$P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......$

where, n = number of trials (samples) taken = 12 people

r = number of success = 6 survived

p = probability of success which in our question is probability of

one-year survival rate for pancreatic cancer, i.e; p = 20%

Let X = Number of people survived one year

So, X ~ Binom(n = 12 , p = 0.20)

Now, the probability that 6 survived one year is given by = P(X = 6)

P(X = 6) = $\binom{12}{6} \times 0.20^{6} \times (1-0.20)^{12-6}$

= $924 \times 0.20^{6} \times 0.80^{6}$

= 0.0155

5 0

4 years ago