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Tju [1.3M]
3 years ago
13

93 times 10 to the sixth power

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0
93 x 10^6 =
93 x 1,000,000 = 93,000,000
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I put my bag here and my parents stored theirs at there feet​
Ganezh [65]

Answer:

Step-by-step explanation:

You and your parents have a bag and you both stored them at ur feet

4 0
3 years ago
Use the definition of the derviative to compute the derivative of f(x)= 1- 7x^2 at the specific point x=2.
GaryK [48]

Answer:

f'(x) = -28 \ at  \ x = 2

Step-by-step explanation:

f'(2) =  \lim_{h \to 0}\frac{f(2+h)) -f(2)}{h} \\\\f(2+h) = 1 - 7(2+h)^2 = 1 - 7(4 +h^2 +4h) = 1 - 28 - 7h^2 - 28h = - 7h^2 -28h - 27\\\\f(2) = 1 - 7(2^2) = 1 - 28 = -27\\\\f(2+h) - f(2) = -7h^2 - 28h - 27 - (-27) = -7h^2 -28h -27 + 27 = -7h^2 -28h\\\\f'(2) =   \lim_{h \to 0}\frac{-7h^2 - 28h}{h} \\\\

       = \lim_{h \to 0} \frac{h(-7h -28)}{h}\\\\= \lim_{h \to 0} (-7h -28)}\\\\= -7 (0) - 28\\\\= -28

4 0
3 years ago
Whats -12j > 156 , and n+4 +2n < -20 and also -1/2 k - 14 <11
yKpoI14uk [10]
For the first one it is, j<<span>−<span>13
Second one, </span></span>n<<span>−<span>8
</span></span>Third one, k><span>−<span>50</span></span><span>

</span>
8 0
3 years ago
When a constant force acts
yan [13]

Answer:

25

Step-by-step explanation:

First expression: A= k/M

when A = 15 and M = 5, k = A×M = 75

therefore, when M = 4, A = 75/3 = 25

7 0
2 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
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