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oee [108]
3 years ago
15

What is the unit rate if 12 pairs of socks sell for 5.79?

Mathematics
2 answers:
laila [671]3 years ago
7 0


12/5.79=1/x

12x=5.79(1)

12x=5.79

[divide 12 on both sides]

x=193/400(0.4825)

Iteru [2.4K]3 years ago
4 0
Each one is about 48 cents / .48
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What rule would you allow to test weather (x,y) is on line l
n200080 [17]

Answer:

Step-by-step explanation:

If a point (x, y) lies on a straight line, coordinates of the point will satisfy the equation.

Slope of a line passing through two points C(4, 5) and D(8, 10),

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m = \frac{10-5}{8-4}

m = \frac{5}{4}

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y = \frac{5}{4}x-5+5

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0 = \frac{5}{4}(4)

0 = 5

Which is not true.

Therefore, point B doesn't lie on line CD.

8 0
3 years ago
Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea
asambeis [7]

Answer:

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3 0
3 years ago
The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

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P(A'∩B') = P(A') . P(B')  (only for independent cases)

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Part b)

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Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

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P({A}'\cap {B}') = 0.4 x P({B}')

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P({A}'\cap {B}') = 0.16

i)

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ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
3 years ago
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Naddik [55]

Answer:

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Step-by-step explanation:

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