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3 years ago

1/4 to 1/2 find the percent of change-increase or decrease

2 answers:

8 0

The percent of change would be -33.3% which would then equal a 33.3% decrease (when decimal is rounded)

what I did was turn 1/4 and 1/2 into decimals to make it easier to solve

Svet_ta [14]3 years ago

8 0

It's a decrease 1/4 to 1/2 is a decrease

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Is 1/2 greater than 1/4

Irina-Kira [14]

Yes because there is 1 whole 3/4, 1/2, 1/4
Also 1/4 is 1/2 of 1/2 lol I luv math

4 0

3 years ago

Simplify. Use the distributive property. 5(3x+1)

vlada-n [284]

Answer:

15x+5

Step-by-step explanation:

First you distribute the 5 to the 3x ( 5 times 3x=15x)

Next you distribute the 5 to the 1 (5 times 1=5)

Finally you put the two answers together 15x+1

you cant simplify it anymore because you cannot add 15x to 1

6 0

3 years ago

Please help me I need N Please help please I'm begging

Bad White [126]

58 degrees

Explanation
If you have a triangle with the angle measures of abc as 58 degrees, 102 degrees and 20 degrees you can multiply them in order of abc so 58 degrees is angle a, 102 degrees is angle b and 20 degrees is angle c. Then you just put in angle a for d which would be 58 degrees and angle e for b 102 degrees and angle f for c which would be 20 degrees

3 0

2 years ago

There are 16 ounces in a pound. If Jack has 64 ounces of pasta to make for a dinner party, how many pounds does he have? If he h

Natalka [10]

Hey there! :) How are you? Basically what you said is right.

Question 1: There are 16 oz (ounces) in a pound, so we do 64/16= 4 lbs (pounds).

Question 2: If Jack has 3 pounds of pasta, that would mean he has 48 ounces, since 1 pound is 16 oz, so 16*3= 48 ounces.

Hoped I helped! Have a nice day, and keep smiling! :)

4 0

3 years ago

A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi

34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{X}=n\mu$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{X}=\sqrt{n}\sigma$

It is provided that:

$\mu=\$27\\\sigma=\$18\\n=310$

As the sample size is quite large, i.e. n = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

$P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z$

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let s denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding z-value is, -2.33.

Compute the value of s as follows:

$z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57$

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0

3 years ago