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pochemuha
1 year ago
9

Comparing Relationships with Tables1. Decide whether each table could represent a proportional relationship.If the relationship

could be proportional, what would the constant ofproportionality be?a. How loud a sound is depending on how farDistance toaway you are.Listener (ft)Sound Level(dB)85791020407367Costb. The cost of fountain drinks at Hot Dog Hut.Volume(fluid ounces)($)$1.4920$1.59$1.8930

Mathematics
1 answer:
yan [13]1 year ago
6 0

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y=kx

where

k is the constant of proportionality

Verify each table

table a

Let

x ----> distance

y ----> sound level

For each ordered pair calculate the value of k

k=y/x

so

(5,85) -----> k=85/5=17

(10,79) ----> k=79/10=7.9

the values of k are differents

that means

the table nor represent a proportional relationship

table b

let

x ----> volume

y ----> cost

k=y/x

(16,1.49) ----> k=1.49/16=0.093125

(20,1.59) ----> k=1.59/20=0.0795

the values of k are differents

that means

the table nor represent a proportional relationship

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egoroff_w [7]

Answer:

(3+a)

Step-by-step explanation:

3a + a^2

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Factor out an a in the numerator

a(3+a)

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(3+a)

6 0
2 years ago
Read 2 more answers
At her job, mary works 4 hours on monday, 3 hours on wednesday, and 6 hours on saturday. her boss adds a $10 bonus to her payche
Andru [333]
She worked 4+3+6 hours = 13 hoursso 13x+10 = 120.50
13x=110.50
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8 0
3 years ago
Use the relative frequency approach to estimate the probability of the event. In a certain class of students, there are 8 boys f
In-s [12.5K]

Answer:

P\text{Student will be from Kenilworth}\approx 0.256

Step-by-step explanation:

We have been given that that there are 8 boys from Wilmette, 5 girls from Kenilworth, 9 girls from Wilmette, 5 boys from Glencoe, 5 boys from Kenilworth and 7 girls from Glenoce.

The total number of students from Kenilworth is 5 boys plus 5 girls that is 10 students.

The total number of students in the class would be 8+5+9+5+5+7=39

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}

P\text{Student will be from Kenilworth}=\frac{\text{Number of student from Kenilworth}}{\text{Total number of students}}

P\text{Student will be from Kenilworth}=\frac{10}{39}

P\text{Student will be from Kenilworth}=0.2564102564

P\text{Student will be from Kenilworth}\approx 0.256

Therefore, the probability, that the student will be from Kenilworth, is approximately 0.256.

7 0
3 years ago
The sale is for $30 this is 75 % of the original price find the original price
Sauron [17]
1. $52.80

2. 80

3. 46 people

4. 15 minutes

5. 2%

6. 147.03

I think these answers are correct but I am not 100% sure
6 0
3 years ago
What is the measure of EAB in circle F?<br> 72°<br> 92°<br> 148°<br> 200°
Arada [10]

We have been given a diagram. We are asked find the measure of arc EAB.

First of all, we will find the measure of arcs ED and CB using our given information.

We know that measure of an inscribed angle is half the measure of intercepted arc.

We can see that angle EBC is inscribed angle of arc EDC, so measure of arc EDC will be twice the measure of angle EBC.

\widehat{EDC}=2\times m\angle EBC

\widehat{EDC}=2\times 80^{\circ}

\widehat{EDC}=160^{\circ}

Similarly, we will find the measure of arc DCB.

\widehat{DCB}=2\times m\angle DEB

\widehat{DCB}=2\times 70^{\circ}

\widehat{DCB}=140^{\circ}

\widehat{ED}=\widehat{EDC}-\wdiehat{DC}

\widehat{ED}=160^{\circ}-88^{\circ}

\widehat{ED}=72^{\circ}

\widehat{ED}+\widehat{DCB}+\widehat{EAB}=360^{\circ}

72^{\circ}+140^{\circ}+\widehat{EAB}=360^{\circ}

212^{\circ}+\widehat{EAB}=360^{\circ}

\widehat{EAB}=360^{\circ}-212^{\circ}

\widehat{EAB}=148^{\circ}

Therefore, the measure of arc EAB is 148 degrees and option C is the correct choice.

8 0
3 years ago
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