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daser333 [38]
3 years ago
12

If m∠ABC = 72°, what is m∠DAB? A) 72° B) 108° C) 144° D) 216°

Mathematics
2 answers:
Semmy [17]3 years ago
8 0
∠ABC=∠CDA=72º
∠DAB=∠BCD=x

∠ABC+∠CDA+∠DAB+∠BCD=360º

Therefore:
72º+72º+x+x=360º
144º+2x=360º
2x=360º-144º
2x=216º
x=216º/2
x=108º

So, <span>∠DAB=∠BCD=x=108º

Answer: </span>∠DAB=108º  (B)
Eddi Din [679]3 years ago
4 0

B) 108°

Answer:

B) 108°

Step-by-step explanation:

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Hurry 50 points for correct answer
Ad libitum [116K]

Answer: <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

Step-by-step explanation:

The equation x=\sqrt{6x+7} can be solved by squaring both sides:

x^2 = 6x + 7\\\\x^2 - 6x - 7 = 0\\\\(x-7)(x+1) = 0

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

1 = \sqrt{-1}\\ 7 = \sqrt{49}

The square root of 49 equals 7, but the square root of -1 is an imaginary number.

The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>

4 0
3 years ago
How do i solve for x ​
sergiy2304 [10]

Expplanation and Answer:

y=mx−7

Swap sides so that all variable terms are on the left hand side.

mx−7=y

Add 7 to both sides.

mx=y+7

Divide both sides by m.

m

mx

​

=

m

y+7

​

Dividing by m undoes the multiplication by m.

x=

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​

3 0
3 years ago
A crane lifts 50 Newtons 2 meters. How much work is done
Nikitich [7]

Answer:

100 Joules

Step-by-step explanation:

We use the definition of Work as the force applied multiplied by the distance the object was moved. In our case the force exerted is 50 N, over a distance of 2 meters, therefore:

Work = F * d = 50 N * 2 m = 100 N*m = 100 Joules

The SI unit for Newton times meter is called "Joule".

7 0
3 years ago
The area of a playground is 266 yd. The width of the playground is 5 yd longer than its length. Find th
Mademuasel [1]

Answer:

C

Step-by-step explanation:

The width is 5 yds longer so we can mark out b and d if you multiply 19 and 24 is 456 so you are left with C

5 0
3 years ago
Find the lateral area for the pyramid with the equilateral base.
Dafna11 [192]

Answer:

Option A is the correct answer.

Explanation:

 The given pyramid has 3 lateral triangular side as shown below.

 Base of triangle = 12 unit

 We need to find perpendicular.

  By Pythagoras theorem we have

            Perpendicular² = 10²-6²

           Perpendicular = 8 unit

So area of 1 lateral triangle = 1/2 x Base x Perpendicular.

                                             = 1/2 x 12 x 8 = 48 unit²

Area of lateral side = 3 x 48 = 144 unit²    

Option A is the correct answer.                

7 0
3 years ago
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