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2 years ago

P-please help (30 points)

Mathematics

1 answer:

liubo4ka [24]2 years ago

8 0

Answer:

No .1

Ans ; 2

No.2

Ans ; 3

Step-by-step explanation:

Multiply or add and if the value is whole no. then its W else L

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marco and suzi each mulyiplied 0.721 X 100 Marco got 7.21 for his product suiz got 72.1 for her product which student multiplied

Marianna [84]

Size got it right because it’s multiplied by 100

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2 years ago

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lutik1710 [3]

Pythagorean Theorem: a^2 + b^2 = c^2

-A and B are legs of the triangle

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#1.

6^2 + 8^2 = c^2

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100 = c^2

c = 10

#2.

5^2 + 12^2 = c^2

25 + 144 = c^2

169 = c^2

c = 13

#4.

10^2 + 4^2 = c^2

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116 = c^2

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15^2 + 9^2 = c^2

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306 = c^2

c = $3\sqrt{34}$

#6.

120^2 + b^2 = 150^2

14400 + b^2 = 22500

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#7.

144^2 + b^2 = 194^2

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b^2 = 16900

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4 0

3 years ago

Elliott has 5 1/2 bags of birdseed.He uses 3 2/5 bags to feed the birds at the park.He puts the rest of the birdseed in the bird

andre [41]

Answer:

Elliott put 2.1 bags of birdseed in the feeders

Step-by-step explanation:

(5 1/2) - (3 2/5) = 2.1

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2 years ago

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mixas84 [53]

The answer is option 1

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3 years ago

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

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2 years ago