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3 years ago

10 Pts + Brainliest for the best answer

Mathematics

1 answer:

LenaWriter [7]3 years ago

3 0

m∠PQR = m∠BQR + m∠PQB

We have m∠PQR = 116° and m∠BQR = 75°. Substitute:

116° = 75° + m∠PQB subtract 75° from both sides

41° = m∠PQB

<h3>Answer: m∠PQB = 41°</h3>

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Andrew, Brenda and Cammi all work part-time at a supermarket. Cammi earns $20 more than Andrew

stellarik [79]

Step-by-step explanation:

Let Andrew wage be = X

Cammi earns $20 more than Andrew So Cammi earns = 20 + X

Brenda earns $30 less than twice Andrew's wage

So she earns = 2X - 30

Their total combanied wage is $400

So Andrew + Cammi + Brenda = $400

X + 20+X + 2X-30 =400

4X - 10 =400

4X=400+10

4X=410

X= $102.5

So Andrew earns $102.5

Cammi earns $122.5

Brenda earns $175

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2 years ago

Simplify:9-1÷2÷27^2÷3

sammy [17]

First let's calculate the exponents.

$27^2 : 729 = 9-1\div \:2\div \:729\div \:3$

Now we should multiply and divide.

$1\div2\div729\div3:\frac{1}{4374} = 9-\frac{1}{4374}$

Now we should add and subtract.

$9-\frac{1}{4374} :\frac{39365}{4374} = \frac{39365}{4374}$

Convert the improper fractions into mixed numbers.

$8\frac{4373}{4374}$

Answer :

$8\frac{4373}{4374}$

5 0

3 years ago

PLEASE HELP I WILL MARK BRAINLIEST

Lelu [443]

Answer:

$27 \: {km}^{2}$

Step-by-step explanation:

Given is the shape of a trapezoid.

Therefore,

Area of the trapezoid

$= \frac{1}{2} (2 + 7) \times 6 \\ \\ = 9 \times 3 \\ \\ = 27 \: {km}^{2}$

5 0

3 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

This implies that,

$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .

We substitute this values to obtain,

$-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}$

$\Rightarrow -2=4\pi \frac{dh}{dt}$

$\Rightarrow -1=2\pi \frac{dh}{dt}$

$\frac{dh}{dt}=-\frac{1}{2\pi}$

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3 years ago

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De'Jhan went to the movies during our snow days and watched all 8 Spider-Man movies. Each movie cost $11. How much did De'Jhan s

den301095 [7]

Answer:

$88 is the answer

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2 years ago

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