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4 years ago

The area of triangle JKL is 32 cm². What is the area of the parallelogram JKLM? A. 16 cm² B. 32 cm² C. 64 cm² D. 128 cm²

Mathematics

2 answers:

snow_lady [41]4 years ago

6 0

I hope this helps you

d1i1m1o1n [39]4 years ago

3 0

Answer: 64 cm2

Step-by-step explanation:

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Simone has 5 employees in her flower shop. Each employee works 6 4⁄15 hours per day. How many hours, in total, do the 5 employee

satela [25.4K]

Answer:

94/3 = 31.333

Step-by-step explanation:

The total hours worked = the amount of employees * hours worked

First I converted the mixed fraction 6 $\frac{4}{15}$ into $\frac{94}{15}$

Then I multiplied it by the amount of employees.

$\frac{94}{15}$ * 5 = $\frac{94}{3}$

= 31.33333

4 0

3 years ago

Select the correct product of (a + 8)(b + 3)

EleoNora [17]

) ab + 8a + 3b + 24the correct product of (a + 8)(b + 3)

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4 years ago

Read 2 more answers

Helpppppp mathhh failing

LenKa [72]

Sin60 =b/10
√3/2 = b/10
b = √3 / 2 (10)
b = 5√3

d^2 = 10^2 - (5√3)^2
d^2 = 100 - 75
d^2 = 25
d = 5

sin30 = b/a
1/2 = 5√3 / a

a = 5√3 (2)
a = 10√3

c^2 = (10√3)^2 - (5√3)^2
c^2 = 300 - 75
c^2 = 225
c = 15

so
a =10√3, b = 5√3, c = 15,d = 5
answer is
D. last choice

4 0

4 years ago

3. 1/4 added by 2. 5/6 estimated by each sum or difference

maxonik [38]

let's firstly convert the mixed fractions to improper fractions, and then add.

$\bf \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}~\hfill \stackrel{mixed}{2\frac{5}{6}}\implies \cfrac{2\cdot 6+5}{6}\implies \stackrel{improper}{\cfrac{17}{6}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{13}{4}+\cfrac{17}{6}\implies \stackrel{\textit{we'll use the LCD of 12}}{\cfrac{(3)13~~+~~(2)17}{12}}\implies \cfrac{39+34}{12}\implies \cfrac{73}{12}\implies 6\frac{1}{12}$

3 0

3 years ago

When the domain of a function has an infinite number of values, the range always has an infinite number of values. True or false

iragen [17]

Answer:

Thus, the statement is False!

Step-by-step explanation:

When the domain of a function has an infinite number of values, the range may not always have an infinite number of values.

For example:

Considering a function

$f(x) = 5$

Its domain is the set of all real numbers because it has an infinite number of possible domain values.

But, its range is a single number which is 5. Because the range of a constant function is a constant number.

Therefore, the statement ''When the domain of a function has an infinite number of values, the range always has an infinite number of values'' is FALSE.

Thus, the statement is False!

3 0

3 years ago