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The area of triangle JKL is 32 cm². What is the area of the parallelogram JKLM? A. 16 cm² B. 32 cm² C. 64 cm² D. 128 cm²
2 answers:
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Answer:
Step-by-step explanation:
The given functions are and
.
We now composed the two functions to find:
This function is defined if the denominator is not zero.
We write this in interval notation as:
We need to be cautious here as x=0 is not in the domain of g(x).
Therefore the domain of is
Answer:
- a ≈ 27.65; B = 28°; c ≈ 19.17
- a ≈ 163.30; B = 120°; c ≈ 59.77
- A = 13°; b ≈ 0.3874; c ≈ 1.3737
Step-by-step explanation:
As long as you're seeking outside help, the use of a suitable tool is appropriate. Many graphing calculators, apps, and web sites are available for solving triangles.
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Here, you're given two angles and a side. The third angle is the difference from 180° of the sum of the other two. For example, in the first problem, ...
B = 180° -A -C = 28°
The missing sides are found using the law of sines. Since you are given a side, use that as the reference, and its opposite angle as the reference angle. Then you have ...
side = sin(opposite angle)×<em>((reference side)/sin(reference angle))</em>
Note that the factor in italics remains the same for both remaining sides.
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In the first problem, this becomes ...
a = sin(112°)·14/sin(28°) ≈ 27.65
c = sin(40°)·14/sin(28°) ≈ 19.17
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The remaining problems are worked in similar fashion.
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<em>Comment on triangle solutions</em>
These are straightforward because you're given two angles. If you're given two sides and an angle, the solution method varies depending on which angle you're given (opposite the long side, the short side, or the unknown side). In the last case, the law of cosines is involved. In the second case, there are likely two solutions. Once you have two angles, you can proceed as above.
