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sergij07 [2.7K]
3 years ago
15

Expand the following using either the Binomial Theorem or Pascal’s Triangle. You must show your work for credit.

Mathematics
2 answers:
Setler [38]3 years ago
6 0

Answer:

x^5-25x^4+250x^3-1250x^2+3125 x-3125

Step-by-step explanation:

Here the given expression is,

(x-5)^5

By the binomial theorem,

(p+q)^n=\sum_{r=0}^{n} ^nC_rp^{n-r} q^r

Where,

^nC_r=\frac{n!}{(n-r)!r!}

Thus, by the above formula,

(x-5)^5=\sum_{r=0}^{5} ^5C_rx^{5-r} (-5)^r

=^5C_0x^{5-0} (-5)^0 + ^5C_1x^{5-1} (-5)^1 + ^5C_2x^{5-2} (-5)^2 + ^5C_3x^{5-3} (-5)^3 + ^5C_4x^{5-4} (-5)^4 + ^5C_5x^{5-5} (-5)^5

=(1)(x^5)(1)+(5)(x^4)(-5)+(10)(x^3)(25)+(10)(x^2)(-125)+(5)(x^1)(625)+(1)(1)(-3125)

=x^5-25x^4+250x^3-1250x^2+3125 x-3125

madam [21]3 years ago
3 0
The binomial coefficients are 1,5,10,10,5,1     (5/0, 5/1, 4/2, 3/3, 2/4, 1/5)

x^5-25x^4+250x^3-1250x^2+3125x-3125


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3. In AABC, a = 35, c = 25, and m can be drawn given these measurements?
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Only one triangle possible with angle 38.2° at C.

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Then for this purpose, we all know that the

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Disclaimer: This question was incomplete. Please find the full content below.

Question:

Law of Sines and the Ambiguous Case.

In ∆ ABC, a =35, c = 25, and m < A = 60*

How many distinct triangles can be drawn given these measurements?

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