All categories

3 years ago

90/100÷15 having issues with this problem

1 answer:

5 0

$You're \ asking: 90/100 \ divided \ by \ 15.\\\\Let's \ do \ this \ together \ in \ steps!\\\\Divide.\\9/10 \ divided \ by \ 15.\\\\Make \ a \ fraction.\\\\9/10 \ x \ 1/15\\\\Simplify.\\\\9x1/10x15\\\\Simplify.\\\\9/150\\\\Simplify.\\\\\fbox{3/50}\\\\\bold{Thanks \ for \ using \ Brainly!}$

You might be interested in

True or False??<br> The more mass a body has, the less inertia it has.

OLEGan [10]

Answer:

false

Step-by-step explanation:

bc mass and inertia are directly proportional so if mass increase, inertial will be increase

I=mr2

7 0

3 years ago

Dolve the equation <br> 11q-6=3q+8q

Amanda [17]

Answer:

no solution

Step-by-step explanation:

Simplifying

11q + -6 = 3q + 8q

Reorder the terms:

-6 + 11q = 3q + 8q

Combine like terms: 3q + 8q = 11q

-6 + 11q = 11q

Add '-11q' to each side of the equation.

-6 + 11q + -11q = 11q + -11q

Combine like terms: 11q + -11q = 0

-6 + 0 = 11q + -11q

-6 = 11q + -11q

Combine like terms: 11q + -11q = 0

-6 = 0

Solving

-6 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

6 0

4 years ago

The tread life of tires mounted on light-duty trucks follows the normal probability distribution with a population mean of 60,00

qwelly [4]

Answer:

$S.E=1183.2$

Step-by-step explanation:

From the question we are told that:

Population mean $\mu=60000$

Population standard deviation $\sigma= 14,000 miles.$

Sample size $n=140$

Generally the equation for Standard error is mathematically given by

$S.E=\frac{ \sigma}{ \sqrt n}$

$S.E= \frac{14000}{\sqrt 140}$

$S.E=1183$

6 0

3 years ago

List the first twenty counting numbers in the indicated base below. twelve (Only digits 0, 1, 2, 9, A, B are used in base twelve

Solnce55 [7]

Answer:

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, 10, 11, 12, 13, 14, 15, 16, 17, 18

Step-by-step explanation:

The first twenty counting numbers in base ten are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20. If we convert each of these numbers to base twelve, then we will get the first twenty counting numbers in base twelve. We now proceed with the conversion below.

The first twelve digits of base 12 are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B.

12 in base 10 = 10 in base 12 since 12/12 = 1 R 0.

13 in base 10 = 11 in base 12 since 13/12 = 1 R 1.

14 in base 10 = 12 in base 12 since 14/12 = 1 R 2.

15 in base 10 = 13 in base 12 since 15/12 = 1 R 3.

16 in base 10 = 14 in base 12 since 16/12 = 1 R 4.

17 in base 10 = 15 in base 12 since 17/12 = 1 R 5.

18 in base 10 = 16 in base 12 since 18/12 = 1 R 6.

19 in base 10 = 17 in base 12 since 19/12 = 1 R 7.

20 in base 10 = 18 in base 12 since 20/12 = 1 R 8.

So the next 8 counting numbers of base 12 are 10, 11, 12, 13, 14, 15, 16, 17, 18.

4 0

3 years ago

Solve by substitution y = 2x - 5 and 3y - x = 5

Nostrana [21]

Answer:

(x, y) = (4, 3)

Step-by-step explanation:

The first equation gives an expression for y that can be substituted into the second equation:

3(2x -5) -x = 5

5x -15 = 5 . . . . . . simplify

5x = 20 . . . . . . . .add 15

x = 4 . . . . . . . . . . divide by 5

y = 2(4) -5 = 3 . . substitute for x in the first equation

(x, y) = (4, 3)

Solution by graphing confirms this result.

6 0

3 years ago

90/100÷15 having issues with this problem​

90/100÷15 having issues with this problem