All categories

3 years ago

2.3 repeating as a fraction

Mathematics

2 answers:

ki77a [65]3 years ago

8 0

Answer:

First, we can write:

x = 2 . ¯ 3

Next, we can multiply each side by 10 giving:

10 x = 23 . ¯ 3

Then we can subtract each side of the first equation from each side of the second equation giving:

10 x − x = 23 .¯ 3 − 2 . ¯ 3

We can now solve for x as follows:

10 x − 1 x = ( 23 + 0 . ¯ 3 ) − ( 2 + 0 . ¯ 3 ) ( 10 − 1 ) x = 23 + 0 . ¯ 3 − 2 − 0 . ¯ 3

9 x = ( 23 -2 ) + ( 0 . ¯ 3 − 0 . ¯ 3 )

9 x = 21 + 0

9 x = 21

9 x /9 = 21 /9

9 x /9 = 3 × 7 /3 × 3

x = 3 × 7 /3 × 3

x = 7 /3

Hope this helps!

Plz mark brainliest! ☜(ﾟヮﾟ☜)

Marat540 [252]3 years ago

7 0

23/10 = 2 and 3/10

I hope this helped

You might be interested in

Assessment items Two triangles, both different shades of blue, labeled Figure 1 and Figure 2. One triangle overlaps the other. A

AURORKA [14]

The square was translated 2 units down.

_____
Information related to triangles and line segments appears to have no relevance to any question asked here.

3 0

4 years ago

Write an equation of the perpendicular bisector of the segment with endpoints M(-3,4) and N(9,8).

34kurt

Answer:

<h2>please mark in brain list </h2>

8 0

3 years ago

Tom has 7 more silver dollars than Jimmy. Together they have a total of 71 silver dollars. How many silver dollars does Tom have

Eddi Din [679]

Tom has 39 silver dollars. You can do this on your head. Jimmy has 32, and Tom 39.

4 0

3 years ago

Write an equation for the nth term of the arithmetic sequence: 15,28,41 ....

11111nata11111 [884]

Answer:

The equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

Step-by-step explanation:

We need to write an equation for the nth term of the arithmetic sequence:

15,28,41 ....

The equation for arithmetic sequence is: $a_n=a_1+(n-1)d$

Where $a_n$ is the nth term, $a_1$ is first term and d is common difference

In the given sequence we have:

a₁ = 15

a₂ = 28

We can find common difference using the formula:

$a_n=a_1+(n-1)d\\Put\: n=2, a_2=28\: and\: a_1=15\\a_2=a_1+(2-1)d\\28=15+d\\d=28-15\\d=13$

So, the common difference d is 13

Now, equation for nth term will be:

$a_n=a_1+(n-1)d\\Put\:a_1=15, d=13\\a_n=15+(n-1)13\\Solving:\\a_n=15+13n-13\\a_n=13n+2$

So, the equation for the nth term of the given arithmetic sequence is: $\mathbf{a_n=13n+22}$

where n=1,2,3..

4 0

3 years ago

Hello mere pyaare bhaiyo or bheno

goldfiish [28.3K]

Cz I secretly enter this site

Non of my family knows

Cz they are over protective lol

Only a cousin know

That's why l can't pay to comment

It's sad life bro

5 0

3 years ago

2.3 repeating as a fraction​

2.3 repeating as a fraction