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Ira Lisetskai [31]
2 years ago
6

Work out the value of 2. 4510 ×10to the power of 9 1.15 × 10 to the power of 3

Mathematics
1 answer:
Simora [160]2 years ago
8 0

Answer:

The result in standard form is: 2.3 \times 10^{6}

Step-by-step explanation:

Dividing the values:

To find the real part, we divide 2.645 by 1.15. So

2.645/1.15 = 2.3

Finding the power:

Its a division, so we keep the base, and subtract the exponents. So

\frac{10^9}{10^3} = 10^{9-3} = 10^{6}

Result in standard form:

The result in standard form is: 2.3 \times 10^{6}

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I have taken the test and I can confirm that the answer is

B. 15 m, 20 m, and 25 m.

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4 0
3 years ago
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Please help. Im dying for the explanation. I will mark you brainalist.
AlekseyPX

Step-by-step explanation:

Given that the mean of the numbers is 12

mean =  \frac{sum \:  \: of \: observations}{total \: number \: of \: observations}

so here

let's that one as x and another one as 2x since it is given that one is twice the other

Therefore we get

mean =  \frac{13 + x + 4 + 16 + 6 + 2x}{6}

Given mean = 12

12 =  \frac{39 + 3x}{6}

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5 0
2 years ago
3x − 6y = –6 x = 2 solve using substitution.
nordsb [41]

Answer:

y=2

Step-by-step explanation:

First, you substitute x with 2.

3(2)-6y=(-6)

Then, you multiply:

6-6y=(-6)

Next, you subtract 6 from -6. So, the first 6 gets crossed out because of inverse of operation.

-6y=-12

Finally, you divide -6 to both sides of the equation to get y=2

3 0
2 years ago
Please help! (I'll give brainliest to the first right answer)
Zanzabum

Answer:

Step-by-step explanation:

5 0
2 years ago
If you invest $4,500 in an account paying 2% compounded continuously, how much money will be in the account at the end of 4 year
saveliy_v [14]
Total = Principal * e^(rate*years)
Total = 4,500 * 2.718281828459^(.02*4)
Total = 4,500 * 2.718281828459^(.08)
Total = 4,500 * <span> <span> </span></span> <span> <span> <span> 1.0832870677 </span> </span> </span>
Total = <span> <span> <span> 4,874.79 </span> </span> </span>
calculator for checking the answer:
http://www.1728.org/compint.htm



7 0
2 years ago
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