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butalik [34]
3 years ago
6

Scribe a situation where it is easier to use decimals than fractions

Mathematics
2 answers:
Fantom [35]3 years ago
8 0
In my opinion it is always easier because a fraction like 5/6 and 1/4 is harder to add or subtract than .123 and .421
a_sh-v [17]3 years ago
5 0
Money type situations !!
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In the diagram of a quadrilateral below, the variables represent the length of the sides in inches.
SVETLANKA909090 [29]
Add 11 + 16. Plug in 11 into b-2 since b equals eleven. You should now have 11+16+11-2. Do the same thing and plug in 16 for c and 11 for b for c-b. Your solution will now be 11+16+11-2+16-11.
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Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

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3 years ago
How can I find the volume of this prism? Helpp
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Answer:

152.971

Step-by-step explanation:

i think thats the answer but sorry if its not.

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2 years ago
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Leni [432]

Answer:

G(x)=2x32+c

Step-by-step explanation:

4 0
2 years ago
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