We have that
(14x2 - 3x3 + 9x4) - (-14 + 13x3 + 11x4)=<span>14x2 - 3x3 + 9x4 +14 - 13x3 - 11x4
</span>(14x2 - 16x3 +14 - 2x4)
then
-2x4-16x3+14x2+14=0--------------> this is the <span>standard form
simplify </span><span>dividing the entire expression by two
</span><span>-x4-8x3+7x2+7=0
the answer is
</span>-x4-8x3+7x2+7=0<span>
</span>
Answer:
The area of the sector is 
Step-by-step explanation:
step 1
Find the area of the circle
The area of the circle is equal to

we have
----> the radius is half the diameter
substitute


step 2
Find the area of a sector with a central angle of (2pi/3)
Remember that
The area of
subtends a central angle of 
so
by proportion
Let
x----> the area of the sector

Answer:
B
Step-by-step explanation:
Given
f(x) = x² - 8x + 3
To complete the square
add/subtract ( half the coefficient of the x- term )² to x² - 8x
x² + 2(- 4)x + 16 - 16 + 3
(x - 4)² - 13 ← in vertex form → B
Answer:

Step-by-step explanation:
Based on the given conditions, formulate: 
Calculate the product or quotient: 240
get the result: 240
Answer: 240
To find this answer, we had to use the expression 80 * 3, therefore making it the answer.