Answer:
-3x / 4
Step-by-step explanation:
Answer:
it is -3+11x
Step-by-step explanation:
just look at your notes or take some
Answer:
The test results support the claim
Step-by-step explanation:
The Coca-Cola Company reported that the mean per capita annual sales of its beverages in the United States was 423 eight ounce servings (Coca-Cola Company website, February 3, 2009).
Suppose you are curious whether the consumption of Coca-Cola beverages is higher in Atlanta, Georgia, the location of Coca-Cola’s corporate headquarters.
A sample of 36 individuals from the Atlanta area showed a sample mean annual consumption of 460.4 eight ounce servings with a standard deviation of s = 101.9 ounces. Using α = .05, do the sample results support the conclusion that mean annual consumption of Coca-Cola beverage products is higher in Atlanta?
Hx: u <= 423 oz
Ha: u > 423 oz (claim)
z(460.4) = (460.4-423)/[101.9/sqrt(36)] = 2.2022
p-value = P(z > 2.2022) = 0.0138
Conclusion: Since the p-value is less than 5%
reject Hx at the 5% significance level.
The test results support the claim.
Answer:
-16.1y + 14
Step-by-step explanation:
–7(2.3y − 2)
=> -16.1y + 14
Therefore, -16.1y + 14 is the simplified form.
Hoped this helped
![GeniusUser](https://tex.z-dn.net/?f=GeniusUser)
Answer:
The lateral area is equal to
![LA=64\sqrt{3}\ m^{2}](https://tex.z-dn.net/?f=LA%3D64%5Csqrt%7B3%7D%5C%20m%5E%7B2%7D)
Step-by-step explanation:
In this problem the lateral area is equal to the area of one equilateral triangle multiplied by ![4](https://tex.z-dn.net/?f=4)
To find the area of one equilateral triangle calculate the height
The area of the triangle is equal to
![A=\frac{1}{2}bh](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7Dbh)
we have
![b=8\ m](https://tex.z-dn.net/?f=b%3D8%5C%20m)
Applying the Pythagoras theorem
![h^{2}=8^{2} -4^{2} \\h^{2}=64-16\\ h=\sqrt{48} \\ h=4\sqrt{3}\ m](https://tex.z-dn.net/?f=h%5E%7B2%7D%3D8%5E%7B2%7D%20-4%5E%7B2%7D%20%5C%5Ch%5E%7B2%7D%3D64-16%5C%5C%20h%3D%5Csqrt%7B48%7D%20%5C%5C%20h%3D4%5Csqrt%7B3%7D%5C%20m)
The area of one triangle is equal to
![A=\frac{1}{2}(8)(4\sqrt{3})\ m^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%288%29%284%5Csqrt%7B3%7D%29%5C%20m%5E%7B2%7D)
so
The lateral area is equal to
![LA=4\frac{1}{2}(8)(4\sqrt{3})=64\sqrt{3}\ m^{2}](https://tex.z-dn.net/?f=LA%3D4%5Cfrac%7B1%7D%7B2%7D%288%29%284%5Csqrt%7B3%7D%29%3D64%5Csqrt%7B3%7D%5C%20m%5E%7B2%7D)