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Damm [24]
3 years ago
14

Graph the equation. (x + 3)2 + (y + 2)2 = 16

Mathematics
1 answer:
Sati [7]3 years ago
3 0

okay well first you should put it in slope-intercept form aka y = mx + b

but you have simplify everything first

2(x + 3) + 2(y + 2) = 16

2x + 3 + 2y + 4 = 16

2x + 2y + 7 = 16

              -7    -7  

2x + 2y = 9

-2x          -2x

2y = -2x + 9

/2         /2

y = -x + 4.5

so now in a graph it should look like this:

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Every year, Aunt linda spends $36 on a dozen candy bunnies for her nephews and nieces. This year, she has to buy 15 bunnies. If
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Assume that the one-way commute time of an UoU student from his house to school is a normally distributed random variable which
Marizza181 [45]

Answer:

n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16

So the answer for this case would be n=16 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=10 represent the sample standard deviation

n represent the sample size  

ME=5 represent the margin of error

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (2)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (3)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.96, replacing into formula (3) we got:

n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16

So the answer for this case would be n=16 rounded up to the nearest integer

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192$
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Please help I really do not understand this yeah I can be weird sometimes but please help will mark the correct answers brainies
NISA [10]

Answer:

Step-by-step explanation:

1.0.39

2.0.33

3.Loose

4.0.14

I did the first four... hope that helps

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