Answer:
-68/7
Step-by-step explanation:
slope1 of Car 1 that pass (-5,-8) (2,7)
= (y1-y2)/(x1-x2)=(2-(-5))/(7-(-8))=7/15
Slope2 of car 2 that pass (5,1) (10,y)
slope 1 and slope2 are perpendicular =>slope 2 =-15/7
make slope2 y=(-15/7)x+b
for it pass(5,1) => 1=(-15/7)5+b =>b=82/7 => y=(-15/7)x+82/7
put (10,y) in => y=(-15/7) 10+82/7=-68/7
Answer:
Step-by-step explanation:
The second set. It contains (2,2) and (2,7), so it fails the vertical-line test.
Answer:
f = 3
Step-by-step explanation:
Solve for f:
13 - 6 f = 2 f - 11
Subtract 2 f from both sides:
13 + (-6 f - 2 f) = (2 f - 2 f) - 11
-6 f - 2 f = -8 f:
-8 f + 13 = (2 f - 2 f) - 11
2 f - 2 f = 0:
13 - 8 f = -11
Subtract 13 from both sides:
(13 - 13) - 8 f = -13 - 11
13 - 13 = 0:
-8 f = -13 - 11
-13 - 11 = -24:
-8 f = -24
Divide both sides of -8 f = -24 by -8:
(-8 f)/(-8) = (-24)/(-8)
(-8)/(-8) = 1:
f = (-24)/(-8)
The gcd of -24 and -8 is -8, so (-24)/(-8) = (-8×3)/(-8×1) = (-8)/(-8)×3 = 3:
Answer: f = 3
Answer:
(-∞, -5/2) ∪ (1, ∞)
Step-by-step explanation:
"Increasing" means the graph goes up to the right. It is increasing from the left up to the local maximum--the peak at left.
It is increasing again from the local minimum on the right to the right side of the graph.
The two sections where the graph is increasing are ...
(-∞, -5/2) ∪ (1, ∞)
__
The graph is <em>decreasing</em> between the maximum on the left and the minimum on the right.
Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.
Step-by-step explanation:
We know that, LCM = Least common multiple.
For example : LACM of 12 and 60 is 60.
If LCM of k and 6 is 60.
i.e. the least common multiple of k and 6 is 60.
Since, 10 x 6 = 60.
The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.
Hence, the smallest value of k is 10.
