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3 years ago

how do I find the area of an equilateral triangle given the perimeter of 60 and the height of 17.3 cm?

1 answer:

3 0

If perimeter is 60 so the side is 60 ÷ 3 = 20

Now we can apply the area formula for triangles;

$A=\frac{1}{2}.b.h\\
\\
A=\frac{1}{2}.20.17.3=10.17.3=173 \ cm^2$

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3 years ago

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Answer:

E. FD<DE<EF

Step-by-step explanation:

First I needed to find the other angle which I found by adding the two angles that were given.

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3 years ago

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andreyandreev [35.5K]

Answer:

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Step-by-step explanation:

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3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

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We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

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