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Paul [167]
3 years ago
9

Two experiments are to be performed. The first can result in any one of m possible outcomes. If the first experiment results in

outcome i, then the second experiment can result in any of ni possible outcomes, i = 1, 2, . . . , m. What is the number of possible outcomes of the two experiments
Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0

Answer: The first experiment has M probabilities, and the second has I(m) outcomes, that depends on the result of the first.

And lets call m to the result of the first experiment.

If the outcome of the first experiment is 1, then the second experiment has 1 possible outcome.

If the outcome of the first experiment is 2, then the second experiment has 2 possibles outcomes.

If the outcome of the first experiment is M, then the second experiment has M possibles outcomes.

And so on.

So the total number of combinations C is the sum of all the cases, where we exami

1 outcome for m = 1

+

2 outcomes for m=2

+

.

.

.

+

M outcomes for m = M

C = 1 + 2 + 3 + 4 +...´+M

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Solve for p.<br> -p - 1 = 5 - 9p + 10p
Darina [25.2K]

Answer:

p= 1/3 or 0.33 repeating

Step-by-step explanation:

5-19p=-p-1

5=18p-1

6=18p

divide by 18

6/18 = 1/3 or 0.33 repeating

5 0
3 years ago
Read 2 more answers
Please help with this question asap
stepladder [879]

Pythagoras theorem: leg 1 squared + leg 2 squared = hypotenuse squared

In the diagram, the triangle has angles 90 and 45. So the other angle in the triangle must be 45 degrees as well.  (180 - 90 -45 = 45)

This means it is an isosceles triangle (since two angles are the same), so the two legs have the same length.

So we can say that length of leg1 = x, and the length of leg2 also equals x

Now let's use pythagoras' theorem:

leg1 = x

leg2 = x

hypotenuse = 16

x^2 + x^2 = 16^2

      2x^2 = 16^2

      2x^2  = 256

        x^2 = 128

        x = √(128)

        x = 8√2

3 0
4 years ago
Help me please. <br>Help me please. <br>Help me please.
Gnesinka [82]
A)
To be similar triangles have to have equal angles
triangle ZDB' 
1)angle Z=90 degrees
triangle B'CQ
1) angle C 90 degrees

angle A'B'Q=90
DB'Z+A'B'Q+CB'Q=180, straight angle
DB'Z+90+CB'Q=180
DB'Z+CB'Q=90

triangle ZDB'
DZB'+DB'Z=180-90=90

DB'Z+CB'Q=90
DZB'+DB'Z=90
DB'Z+CB'Q=DZB'+DB'Z
2)CB'Q=DZB' (these angles from two triangles ZDB' and B'CQ )
3)so,angles DB'Z and B'QC are going to be equal because of sum of three angles in triangles =180 degrees and 2 angles already equal.
so this triangles are similar by tree angles
b)
B'C:B'D=3:4
B'D:DZ=3:2
CQ-?
DC=AB=21
DC=B'C+B'D (3+4= 7 parts)
21/7=3
B'C=3*3=9
B'D=3*4=12
B'D:DZ=3:2
12:DZ=3:2
DZ=12*2/3=8
B'D:DZ=CQ:B'C
3:2=CQ:9
CQ=3*9/2=27/2

c)
BC=BQ+QC=B'Q+QC
BQ' can be found by pythagorean theorem



3 0
3 years ago
PLEASE HELP HURRYYY URGENTTT
DENIUS [597]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
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Please Help, I need to know how to graph these equations
devlian [24]
There's a site called m.a.t.h.w.a.y, and you can type in those functions in order to get the graph ;)
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3 years ago
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