Answer:
should I ans?
Step-by-step explanation:
mayb not...coz idu
Help us out please I need this answer right answer too.
Answer:

Step-by-step explanation:
The first step is to use the Distance Formula to figure out the lengths of the two legs:
![\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D](https://tex.z-dn.net/?f=%5Csqrt%7B%5B-x_1%20%2B%20x_2%5D%5E%7B2%7D%20%2B%20%5B-y_1%20%2B%20y_2%5D%5E%7B2%7D%7D%20%3D%20D)
R(1, 1) and P(−1, −2) ↷
![\sqrt{[1 + 1]^{2} + [2 + 1]^{2}} = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\\ \\ \sqrt{13} = RP](https://tex.z-dn.net/?f=%5Csqrt%7B%5B1%20%2B%201%5D%5E%7B2%7D%20%2B%20%5B2%20%2B%201%5D%5E%7B2%7D%7D%20%3D%20%5Csqrt%7B2%5E%7B2%7D%20%2B%203%5E%7B2%7D%7D%20%3D%20%5Csqrt%7B4%20%2B%209%7D%20%3D%20%5Csqrt%7B13%7D%5C%5C%20%5C%5C%20%5Csqrt%7B13%7D%20%3D%20RP)
Q(2, −4) and P(−1, −2) ↷
![\sqrt{[1 + 2]^{2} + [2 - 4]^{2}} = \sqrt{[-2]^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13} \\ \\ \sqrt{13} = QP](https://tex.z-dn.net/?f=%5Csqrt%7B%5B1%20%2B%202%5D%5E%7B2%7D%20%2B%20%5B2%20-%204%5D%5E%7B2%7D%7D%20%3D%20%5Csqrt%7B%5B-2%5D%5E%7B2%7D%20%2B%203%5E%7B2%7D%7D%20%3D%20%5Csqrt%7B4%20%2B%209%7D%20%3D%20%5Csqrt%7B13%7D%20%5C%5C%20%5C%5C%20%5Csqrt%7B13%7D%20%3D%20QP)
* So, by my calculations, we have an isosceles <em>right triangle</em>, and according to the <em>45°-45°-90° triangle theorem</em>, we automatically know that the hypotenuse, <em>RQ</em>, is
:
30°-60°-90° triangle theorem
2x, x, x√3
↑ ↑ ↑
h leg leg
y
p
o
t
e
n
u
s
e
45°-45°-90° triangle theorem
x√2, x, x
↑ ↑ ↑
h legs
y
p
o
t
e
n
u
s
e
So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles <em>right</em><em> </em><em>triangle</em><em>,</em><em> </em>it does not matter:
![[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bh%7D%7B2%7D%5D%5Bb%5D%20%3D%20A%20%5C%3A%20%5C%3AOR%5C%3A%20%5C%3A%20%5B%5Cfrac%7Bb%7D%7B2%7D%5D%5Bh%5D%20%3D%20A%20%5C%3A%20%5C%3AOR%20%5C%3A%20%5C%3A%20%5Cfrac%7Bhb%7D%7B2%7D%20%3D%20A)
![[\frac{\sqrt{13}}{2}][\sqrt{13}] = \frac{13}{2} = 6\frac{1}{2} \\ \\ 6\frac{1}{2} = A](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Csqrt%7B13%7D%7D%7B2%7D%5D%5B%5Csqrt%7B13%7D%5D%20%3D%20%5Cfrac%7B13%7D%7B2%7D%20%3D%206%5Cfrac%7B1%7D%7B2%7D%20%5C%5C%20%5C%5C%206%5Cfrac%7B1%7D%7B2%7D%20%3D%20A)
I am joyous to assist you anytime.
Answer:
The answer is 6 1/5 feet in width.
Step-by-step explanation:
Since the formula for area is <em>wl</em> or <em>width </em>x <em>length</em>, we can utilize our reversive property to find our width by dividing the Area we are given by our length, giving us the missing width in return. Dividing 46.5 square feet by 7.5 feet gives us 6.2 feet, or 6 1/5 feet.
Hope this helps!