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Ksenya-84 [330]
3 years ago
10

Is 4 to 7 the same as 7 to 4? Explain why or why not

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0
Yes

Step-by-step explanation:
4×7=28
and 7×4 also equal to 28
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A circle has a radius of 3it has an arc with a 20 degree central angle
alexandr402 [8]

Answer:

Step-by-step explanation:

The circumference of the circle is 6π inches  

The length of the arc is (20/360)×6π = 1.04 inches  

(The complete circumference would cover 360°. Angle ALB is 20°)

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3 years ago
What do the factors (x+2)(-8x+70)in the factored form represent?
Tasya [4]

Answer:

-2(x+2)(4x-35)

Step-by-step explanation:

5 0
3 years ago
Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

\lim_{x \to 2} f(x) = 1

\lim_{x \to 2} g(x) = -4

\lim_{x \to 2} h(x) = 0

a) Applying properties of limits

\lim_{x \to 2} f(x) + 5g(x) =  \lim_{x \to 2} f(x) + 5  \lim_{x \to 2} g(x) = 1 + 5*-4 = -19

b) Applying properties of limits

\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64

c) Applying properties of limits

\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1

d) Applying properties of limits

\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16

e) Applying properties of limits

\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0

f) Applying properties of limits

\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0

3 0
3 years ago
1) Given a (x) =6x+2 and b (x) = -8x -11
Elenna [48]
I hope this helps you

8 0
3 years ago
The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone'
Sladkaya [172]
The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone's velocity just before it strikes the ground? 

Answer: In order to find the stone’s velocity just before it strikes the ground we will use one of the free fall equations. V = √(2gh). We already have the values needed which are the gravity (9.8 m/s2) and our total height (318 meters). All you have to do is solve for V. You should get 78.95 m/s. 
5 0
3 years ago
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