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3 years ago

Is 4 to 7 the same as 7 to 4? Explain why or why not

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

8 0

Yes

Step-by-step explanation:
4×7=28
and 7×4 also equal to 28

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Brianne's town is building a pool based on a scale drawing that is 20 centimeters by 10 centimeters and uses the scale 1 cm:250

kiruha [24]

Answer:

$A=1250m^2$

Step-by-step explanation:

From the question we are told that

Dimension of drawing

20 centimetres by 10 centimetres

Scale of drawing

1 cm:250 cm

Generally the the Main dimension of the pool is mathematically given as

$L=length\ of\ scaled\ pool*250 cm\\B=length\ of\ scaled\ pool*250 cm\\L=20*250=5000 cm=50m\\B=10*250=2500 cm=25m$

Therefore Area Aof main pool is mathematically given as

$A=50m*25m=1250 m^2$

$A=1250m^2$

4 0

3 years ago

Can you please help me and thank youuu ❤️❤️❤️❤️❤️❤️

alexandr402 [8]

Don’t listen to the people Who give you links You’re trying to scam

3 0

2 years ago

What is a34 of the sequence 9,6,3,

lions [1.4K]

Step-by-step explanation:

What is a34 of the sequence 9,6,3,..

r=a2-a1

r=6-9

r=-3

a34=a1+33.r

a34=9+33.(-3)

a34= 9-99

a34= -90

hope this helps !

bye !

8 0

3 years ago

Read 2 more answers

An adult meerkat weighs 0.786 kilograms. This is 747 grams more than the weight of a baby meerkat. How much does a baby meerkat

liraira [26]

0.786 kg = 786 g

An adult meerkat weighs 786g

786 - 747 = 39g

A baby meerkat weighs 39g

Answer: A baby meerkat weighs 39g

3 0

3 years ago

A questionnaire to assess knowledge of communicable diseases was administered. There were a total of 36 questions to which respo

Zinaida [17]

Answer:

Confidence interval: (1.95,4.45)

Step-by-step explanation:

We are given the following information:

U.S Scores

$\bar{x}_1 = 20.6, s_1 = 5.8, n_1 = 185$

Mexico Scores

$\bar{x}_2 = 17.4, s_2 = 5.8, n_2 = 86$

Formula:

Degree of freedom = $n_1 + n_2 -2 = 185 + 86 -2 = 269$

Confidence interval:

$(\bar{x}_1 - \bar{x}_2) \pm t_{critical}\bigg(\sqrt{\displaystyle\frac{s_1^2}{n_1} + \displaystyle\frac{s_2^2}{n_2}}\bigg)$

Putting the values, we get,

$t_{critical}\text{ at}~\alpha_{0.10}\text{ and degree of freedom 269} = \pm1.6505$

$(20.6-17.4) \pm 1.6505\bigg(\sqrt{\displaystyle\frac{33.64}{185} + \displaystyle\frac{33.64}{86}}\bigg)= 3.2 \pm 1.25 = (1.95,4.45)$

7 0

3 years ago