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weeeeeb [17]
4 years ago
12

What is 2x^2+9x-18 in vertex form?

Mathematics
1 answer:
atroni [7]4 years ago
7 0

Complete the square:

2<em>x</em>² + 9<em>x</em> - 18

2(<em>x</em>² + 9/2 <em>x</em>) - 18

2(<em>x</em>² + 9/2 <em>x</em> + 81/16 - 81/16) - 18

2(<em>x</em>² + 2 (9/4) <em>x</em> + (9/4)²) - 81/8 - 18

2(<em>x</em> + 9/4)² - 225/8

If you're not familiar with the method, the idea is to get a quadratic from the standard form

<em>ax</em>² + <em>bx</em> + <em>c</em>

into its vertex form

<em>a</em> (<em>x</em> - <em>h</em>)² + <em>k</em>

where (<em>h</em>, <em>k</em>) is the vertex of the parabola associated with the quadratic.

Expand the vertex form to get

<em>a</em> (<em>x</em>² - 2<em>xh</em> + <em>h</em>²) + <em>k</em>

<em>ax</em>² - 2<em>ahx</em> + <em>ah</em>² + <em>k</em>

For the two forms to be equivalent, we must have

-2<em>ah</em> = <em>b</em>

<em>ah</em>² + <em>k</em> = <em>c</em>

which means

<em>h</em> = -<em>b</em>/(2<em>a</em>)

<em>k</em> = <em>c</em> - <em>ah</em>² = <em>c</em> - <em>b</em>²/(4<em>a</em>)

In this case, <em>a</em> = 2, <em>b</em> = 9, and <em>c</em> = -18, so

<em>h</em> = -9/(2 • 2) = -9/4

<em>k</em> = 18 - 9²/(4 • 2) = -225/8

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What is the measure of x°?<br><br> 1. 90°<br> 2. 101°<br> 3. 114°<br> 4. 111°
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114

Step-by-step explanation:

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Order the side lengths , , , , and from least to greatest.
diamong [38]

Answer:

1. FH, 2. GH,  3.IH  4. GI,  5. FG

Step-by-step explanation:

According to a certain geometric theorem, the smallest angle is always opposite to the smallest side of a triangle. Likewise, the largest angle is always opposite to the largest side. Using this theorem we can properly order the angles and sides.

Additionally, the interior degrees of a triangle will always be 180, and the interior of this quadrilateral is 360 degrees. Using this we can determine the missing angles.

180 - 75 - 55 = 50 (first missing angle)

180 - 59 - 63 = 58 (second missing angle)

The smallest angle would be 50 degrees and the largest 75.

The second smallest is 55 degrees, the third smallest is 58 degrees, the fourth smallest is 59 degrees, and the fifth is 63 degrees.

Now, one thing that seems a bit confusing is the fact that GH is opposite to 2 different angles, so how do we know WHICH angle to use to find its length. From what I understand, we should be able to find the average of the two angles across from this side to see what its place would be in terms of length.

63 + 50 = 56.5

This would make side  GH larger than FH but less than HI

This is how I would solve the problem, and I think this is the correct order. Please let me know whether it turns out right.

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The probability that a lab specimen contains high levels of contamination is 0.14. A group of 4 independent samples are checked.
Shtirlitz [24]

Answer:

a) 0.5470 = 54.70% probability that none contain high levels of contamination.

b) 0.3562 = 35.62% probability that exactly one contains high levels of contamination.

c) 0.4530 = 45.30% probability that at least one contains high levels of contamination.

Step-by-step explanation:

For each sample, there are only two possible outcomes. Either they contain high levels of contamination, or they do not. The samples are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a lab specimen contains high levels of contamination is 0.14.

This means that p = 0.14

A group of 4 independent samples are checked.

This means that n = 4

(a) What is the probability that none contain high levels of contamination?

This is P(X = 0)

P(X = 0) = C_{4,0}.(0.14)^{0}.(0.86)^{4} = 0.5470

0.5470 = 54.70% probability that none contain high levels of contamination.

(b) What is the probability that exactly one contains high levels of contamination?

This is P(X = 1)

P(X = 1) = C_{4,1}.(0.14)^{1}.(0.86)^{3} = 0.3562

0.3562 = 35.62% probability that exactly one contains high levels of contamination.

(c) What is the probability that at least one contains high levels of contamination?

Either none of the samples contain high levels of contamination, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.5470 = 0.4530

0.4530 = 45.30% probability that at least one contains high levels of contamination.

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