<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>6</em><em>5</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>G</em><em>ood</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>ã</em><em>g</em><em>y</em><em>â</em>
62.8cm^2 I think that's the answer
Answer:
Step-by-step explanation:
use the Pythagorean theorem to find the length of the third sides.
c²=a²+b²
c²=7²+3²
=49+9
=58
so, c²=√58
area of the square is 58 units
Answer:
1.59C + 2.25A = 786.75
C + A = 33 (even if all were the higher paying adults, that would only be 33x2.25=74.25 far less than <<786.75)
1.59C + 1.59A = 33(1.59) = 52.47 subtract to eliminate C
(2.25-1.59)A = 786.75 -52.47 = 734.28
.66A = 734.28
A = 73428/66 = 1112.55 = about 1113 adults
C = 33-1113 = -1080 children
which makes no sense. over a thousand "negative" children? the public pool gave refunds to over a thousand prepaid children who didn't show up? but a public swimming pool, no matter how large, probably wouldn't accomodate 1113 adults.
Step-by-step explanation:
