For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
Z/3+10=-7/10
multiply both sides
10z + 300 = -21
move the constant to the right
10z= -21 - 300
Calculate
10z = -321
divide both sides ^^
answer : z=-321/10
Answer:
the answer is D
Step-by-step explanation:
180-115 = 65