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max2010maxim [7]
4 years ago
7

a cylindrical container is to be pacjed into a cubical box. The length of the box is (2p-4). write the expression for the area o

f the base of the box occupied by the container.(let π = 22\7)​
Mathematics
1 answer:
Dvinal [7]4 years ago
3 0

Answer:

Step-by-step explanation:

diameter = length of the box = 2p - 4 = 2(p - 2)

radius r = 2(p-2)/2 = p - 2

Area of the box occupied by container = πr² = 22/7 * (p-2)²

=\frac{22(p-2)^{2}}{7}

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The answer would be answer choice a.

Because 5/4 = 1.25
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tan (45) = 1
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tan (57) = 1.5399

The closest to 1.25 is tan (51)

Hope this helps :)
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Answer:

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Step-by-step explanation:

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3 years ago
0.25q+0.10d=4.95<br> D=3q
lorasvet [3.4K]
0.25q + 0.1d = 4.95
d = 3q

0.25q + 0.1(3q) = 4.95
    0.25q + 0.3q = 4.95
               <u>0.55q</u> = <u>4.95</u>
                0.55     0.55
                      q = 9
0.25(9) + 0.1d = 4.95
    2.25 + 0.1d = 4.95
  <u>- 2.25             - 2.25</u>
               <u>0.1d</u> = <u>2.7</u>
                0.1     0.1
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Step-by-step explanation:

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