The sum of 12 and a number
(12 + n)
is no greater
< =
then the sum of twice the number and 8
(2n +(-8)) = (2n - 8)
so we have :
(12 + n) < = (2n - 8)
A=6
B= -1/2
C= 11
I had this one on my test and I got it right have a good day
Answer:226.2
Step-by-step explanation
Lateral= 2πrh
H=12
R=3
2*π*3*12=226.19
Round to nearest 10th is 226.2
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.
1.5
i
1.5i