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3 years ago

There are 3 triangles 6 squares what is the simplest ration of the triangles to total shape

Mathematics

2 answers:

malfutka [58]3 years ago

8 0

Answer:

it either can be 3:6 or 6:3 but I think its 3:6

adell [148]3 years ago

7 0

Answer:

1 : 3.

Step-by-step explanation:

The total number of shapes is 3 + 6 = 9.

So triangles : total shapes = 13 : 9

= 1 : 3.

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4 years ago

Read 2 more answers

Distributive Property Using GCF<br><br> 25 + 30

postnew [5]

Hey there! I'm happy to help!

Let's look at the factors of each of these numbers.

1,25

5,5

1,30

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The greatest common factor between these is 5. Therefore, we divide 25+30 by 5 and put the 5 on the outside.

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This has the same value but it is just written differently.

Have a wonderful day! :D

3 0

3 years ago

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Digiron [165]

Answer:

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3 0

3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago