3 years ago

I N33D 3XT4 H3LP 4S4P PLZ!!!!

1 answer:

6 0

$a^n=\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\----------------\\\\\left(\dfrac{5}{3}\right)^3=\dfrac{5}{3}\cdot\dfrac{5}{3}\cdot\dfrac{5}{3}=\dfrac{5^3}{3^3}=\dfrac{125}{27}$

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Find the real number root

noname [10]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

How do you solve :<br><br><img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20" id="Tex

Neporo4naja [7]

$x^2=\dfrac{2}{3}\to x=\pm\sqrt{\dfrac{2}{3}}\\\\x=-\dfrac{\sqrt{2}}{\sqrt3}\ \vee\ x=\dfrac{\sqrt2}{\sqrt3}\\\\x=-\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\ \vee\ x=\dfrac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}\\\\\boxed{x=-\dfrac{\sqrt6}{3}\ \vee\ x=\dfrac{\sqrt6}{3}}$