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Misha Larkins [42]

3 years ago

12

Pls help Alissa’s budget is shown in the circle graph below her total monthly budget is $1,500. How much dose Alissa spend on re

nt

1 answer:

Tju [1.3M]3 years ago

6 0

<em>The answer is</em><em> $300</em><em>......</em>

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All rectangles are paralloelograms

Anni [7]

Answer:

not all rectangles are paralloelograms.

Step-by-step explanation:

8 0

3 years ago

Michelle has a jar of quarters and dimes totalling to 3.10 if there are sixteen coins in the jar how many more quarters are ther

Sav [38]

Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10

0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes

q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters

so there are (10 - 6) = 4 more quarters then dimes

5 0

3 years ago

Bryce has a rug that is 14 decimeters by 16 decimeters. Draw a sketch of Bryce'srug. Then find the area of his rug. Show your wo

yuradex [85]

Answer:

the answer is 224 decimeters

Step-by-step explanation:

first you need to draw a box than label the length and with which is 14 by 16 and then you can use the formula A=L*W. Know you can plug the numbers in 14*16 which equals 224 and that would be your answer

4 0

3 years ago

There are 8 cans of soup there are 3times as many cans of vegetables how many cans of vegetables are there write an equation to

kicyunya [14]

8(number of soup) times 3 =x (number of vegetable cans)

4 0

3 years ago

Read 2 more answers

Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was

andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 100, p = 0.42$

92% confidence level

So $\alpha = 0.08$ , z is the value of Z that has a pvalue of $1 - \frac{0.08}{2} = 0.96$ , so $Z = 1.75$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064$

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0

4 years ago