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Bas_tet [7]
4 years ago
6

Write a word problem that can be modeled by the expression 193 / 14

Mathematics
2 answers:
Kay [80]4 years ago
4 0

Answer:

I had 193 cookies and 14 friends. I have to share it between them since i didn't want any. how many cookies will each of them get/recieve?

Step-by-step explanation:

Brums [2.3K]4 years ago
4 0

Answer:I have 193 people in 14 classrooms, how do you write this as a(n) fraction?

Step-by-step explanation:

I have 193 people in 14 classrooms, how do you write this as a(n) fraction?

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A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample stand
Tpy6a [65]

Answer:

We conclude that the population mean is different from 10.5.

Step-by-step explanation:

We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.

<em>We have to test the claim that the population mean is 10.5.</em>

Let, NULL HYPOTHESIS, H_0 : \mu = 10.5  {means that the population mean is 10.5}

ALTERNATE HYPOTHESIS, H_a : \mu \neq 10.5  {means that the population mean is different from 10.5}

The test statistics that will be used here is One-sample t-test;

           T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean = 11

            s = sample standard deviation = 2

            \mu = population mean

            n = sample of values = 16

So, <u>test statistics</u> =  \frac{11-10.5}{\frac{2}{\sqrt{16} } } ~ t_1_5

                            = 1

<em>Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the population mean is different from 10.5.

6 0
4 years ago
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