Plz help its my last grade and i really need it to be good
2 answers:
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A) Let x stand for time, y stand for velocity.
We are given the points (2,50), (6, 54). We can make a line using the slope intercept form
y = mx + b.
slope is (54 - 50)/(6-2) = 4/4 = 1
y = 1x + b
plug in point (2,50) to find b
50 = 1(2) + b
50-2 = b
48 = b
the equation is y = 1x + 48
Make standard form.
<span>x - y = -48
</span><span>b) make a table and plot points for the first 7 hours
Table Is attached.
Good Luck!
If you like the answer please give me brainliest answer!
</span>
We are given the points (2,50), (6, 54). We can make a line using the slope intercept form
y = mx + b.
slope is (54 - 50)/(6-2) = 4/4 = 1
y = 1x + b
plug in point (2,50) to find b
50 = 1(2) + b
50-2 = b
48 = b
the equation is y = 1x + 48
Make standard form.
<span>x - y = -48
</span><span>b) make a table and plot points for the first 7 hours
Table Is attached.
Good Luck!
If you like the answer please give me brainliest answer!
</span>
Answer:
and
Step-by-step explanation:
A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.
In when x=3, y=15/4≈2.14
In when x=3, y=1.8
In when x=3, y≈2.33
In when x=3, y≈1.90
We can observe that in two cases, and
, y is greater than 2.