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Andreyy89
4 years ago
10

With increased concentration, temperature, and pressure, there is also an increased chance that a chemical reaction will occur.

What do all these factors have in common?
Mathematics
2 answers:
klasskru [66]4 years ago
7 0

Answer:

A chemical reaction will occur

Hope this helps

Love,

Morgan Malice

Montano1993 [528]4 years ago
4 0

Answer: increased particle collisions

Step-by-step explanation: Is the correct answer on Edge

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Answer:

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Step-by-step explanation:

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6 0
3 years ago
A bike rental company charges a fee per hour. The charge, in dollars, is the same each hour. The ordered pairs (3, 13.50) and (5
olchik [2.2K]

If the function is y = 4.5x. Then the rate of change of the function expressed as a unit rate will be 4.5.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

A bike rental company charges a fee per hour.

The charge, in dollars, is the same each hour.

The ordered pairs (3, 13.50) and (5, 22.50) represent the corresponding hours, x, and cost, y.

Then the linear equation is given as

\begin{aligned} \rm  y - 22.5 &= \rm \dfrac{22.5 - 13.5}{5 - 3} (x-  5)\\\\\rm y - 22.5 &= \rm 4.5x - 22.5\\\\\rm y &= \rm 4.5x \end

Then the rate of change of the function expressed as a unit rate will be

\rm \dfrac{dy}{dx}  = \dfrac{d}{dx} (4.5x )\\\\\dfrac{dy}{dx}  = 4.5

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

7 0
2 years ago
Jessica has a shelf that is 26 inches long . If she cuts off 12 3/8 inches what is the new length of the shelf ?
maw [93]
14 and 5/8 inches long now
5 0
3 years ago
Your friend asks if you would like to play a game of chance that uses a deck of cards and costs $1 to play. They say that if you
gtnhenbr [62]

Answer:

Expected value = 40/26 = 1.54 approximately

The player expects to win on average about $1.54 per game.

The positive expected value means it's a good idea to play the game.

============================================================

Further Explanation:

Let's label the three scenarios like so

  • scenario A: selecting a black card
  • scenario B: selecting a red card that is less than 5
  • scenario C: selecting anything that doesn't fit with the previous scenarios

The probability of scenario A happening is 1/2 because half the cards are black. Or you can notice that there are 26 black cards (13 spade + 13 club) out of 52 total, so 26/52 = 1/2. The net pay off for scenario A is 2-1 = 1 dollar because we have to account for the price to play the game.

-----------------

Now onto scenario B.

The cards that are less than five are: {A, 2, 3, 4}. I'm considering aces to be smaller than 2. There are 2 sets of these values to account for the two red suits (hearts and diamonds), meaning there are 4*2 = 8 such cards out of 52 total. Then note that 8/52 = 2/13. The probability of winning $10 is 2/13. Though the net pay off here is 10-1 = 9 dollars to account for the cost to play the game.

So far the fractions we found for scenarios A and B were: 1/2 and 2/13

Let's get each fraction to the same denominator

  • 1/2 = 13/26
  • 2/13 = 4/26

Then add them up

13/26 + 4/26 = 17/26

Next, subtract the value from 1

1 - (17/26) = 26/26 - 17/26 = 9/26

The fraction 9/26 represents the chances of getting anything other than scenario A or scenario B. The net pay off here is -1 to indicate you lose one dollar.

-----------------------------------

Here's a table to organize everything so far

\begin{array}{|c|c|c|}\cline{1-3}\text{Scenario} & \text{Probability} & \text{Net Payoff}\\ \cline{1-3}\text{A} & 1/2 & 1\\ \cline{1-3}\text{B} & 2/13 & 9\\ \cline{1-3}\text{C} & 9/26 & -1\\ \cline{1-3}\end{array}

What we do from here is multiply each probability with the corresponding net payoff. I'll write the results in the fourth column as shown below

\begin{array}{|c|c|c|c|}\cline{1-4}\text{Scenario} & \text{Probability} & \text{Net Payoff} & \text{Probability * Payoff}\\ \cline{1-4}\text{A} & 1/2 & 1 & 1/2\\ \cline{1-4}\text{B} & 2/13 & 9 & 18/13\\ \cline{1-4}\text{C} & 9/26 & -1 & -9/26\\ \cline{1-4}\end{array}

Then we add up the results of that fourth column to compute the expected value.

(1/2) + (18/13) + (-9/26)

13/26 + 36/26 - 9/26

(13+36-9)/26

40/26

1.538 approximately

This value rounds to 1.54

The expected value for the player is 1.54 which means they expect to win, on average, about $1.54 per game.

Therefore, this game is tilted in favor of the player and it's a good decision to play the game.

If the expected value was negative, then the player would lose money on average and the game wouldn't be a good idea to play (though the card dealer would be happy).

Having an expected value of 0 would indicate a mathematically fair game, as no side gains money nor do they lose money on average.

7 0
2 years ago
Evaluate by using suitable property: (-343) x (-12) + (-343) x (-88) . Mention the property used.​
Natalka [10]

Answer:

26,068

Step-by-step explanation:

(-343) x (-12) + (-343) x (-88)

= -4116 + 30,184

= 26,068

4 0
3 years ago
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