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2 years ago

What is 7.9 × 103 in standard form?

Mathematics

1 answer:

svet-max [94.6K]2 years ago

4 0

The answer is 813.7 your welcome

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1. The function of lenses is based on the law of refraction. A light beam is traveling from the medium 1 where its speed is V1,

masha68 [24]

Answer:

The index of refraction for Medium 2 would be 1.25

Step-by-step explanation:

We have the following data:

Speed of light in Medium 1 = V₁

Speed of light in Medium 2 = V₂

The speed of Light in Medium 2 is related to speed of light in Medium 1 as:

V₂ = 0.8 V₁

Moreover, it is given that Medium 1 is air with index of refraction equal to 1. i.e.

n₁ = 1

We need to find the index of refraction for medium 2. Lets name it is as n₂.

Snell's law related the above mentioned 4 quantities by following relation:

The ratio of indices of refraction of 2 mediums is equivalent to the reciprocal of ratio of phase velocities in those 2 mediums. Mathematically, this can be written as:

$\frac{n_{1}}{n_{2}} = \frac{V_{2}}{V_{1}}$

Substituting the values we have gives us:

$\frac{1}{n_{2}}=\frac{0.8V_{1}}{V_{1}} \\\\\frac{1}{n_{2}}=0.8\\\\ 1=0.8n_{2}\\\\\frac{1}{0.8}=n_{2}\\\\ n_{2}=1.25$

This means, the index of refraction for Medium 2 would be 1.25

3 0

2 years ago

Divide 70 in the ratio 2:5

Serggg [28]

Answer:

Step-by-step explanation:

20:50

4 0

2 years ago

PLEASE HELP I ONLY HAVE UNTIL 9:30 TO COMPLETE THIS (It's 9:07) PLEASE ANSWER ALL THREE!!!

Gekata [30.6K]

Answer:

1 a 2d 3a

Step-by-step explanation:

hope this help even though I'm late

5 0

2 years ago

Jessica's heart beats 12 times in 1/6 minute how many times does her heart beat each minute

Charra [1.4K]

Answer:

Step-by-step explanation:

12 6 times equals 72.

12x6=72

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20%7D%7Bxy%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%7B4xy%7D%5E%

hjlf

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{3x^2}{xy}\cdot \cfrac{4xy^2}{\frac{1}{y}}\implies \cfrac{3x^2}{xy}\cdot \cfrac{4xy^2}{y^{-1}}\implies \cfrac{3x^2x^1y^2}{xy^1y^{-1}}\implies \cfrac{3x^{2+1}y^2}{xy^{1-1}}
\\\\\\
\cfrac{3x^3y^2}{xy^0}\implies \cfrac{3x^3y^2}{x^1}\implies 3x^3y^2x^{-1}\implies 3x^{3-1}y^2\implies 3x^2y^2$

6 0

2 years ago