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trapecia [35]
3 years ago
9

The tempature is -3 degress.The temperature is expected to decrease 2.5 degress each hour until the temperature reaches -18 degr

ess. How many hours will it take to reach -18? A 6hours
B 7 hours
C 7.2 hours
D 8.4 hours
Mathematics
1 answer:
Andrews [41]3 years ago
6 0

We can set this problem up as an algebraic equation, which we can then solve to find our answer.


We start at -3. So we can start our equation with that:

-3


However, this doesn't represent any change in temperature, just that we start at -3. To show change, we will use the variable x, where x stands for the number of hours. Each hour accounts for a change of -2.5 in degrees, meaning that we must multiply our x by -2.5. We can now add this term into our equation:

-3 - 2.5x


We are trying to find when we will reach -18 degrees, so we will set our entire equation equal to -18 and solve:

-3 - 2.5x = -18

-2.5x = -15

x = 6


It will take us 6 hours, or choice A.

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At 2:00 P.M., a thermometer reading 80 degrees F is taken outside, where the are temperature is 20 degrees F. At 2:03 P.M., the
alex41 [277]
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38=9<span>e<span>^−.3344t</span></span></span> for t
this time we get

<span><span>38 / 9</span>=<span>e^<span>−.3344t</span></span></span>
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4 0
3 years ago
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the performing arts department put in its spring show on Friday and Saturday nights. the price of a ticket was the same both nig
Galina-37 [17]
Let p= the price of a ticket
Let c= the cost to put on the show

Formula:
(profit) = (ticket price) * (number of people) - (cost to put on show)
We have two equations here:
500=120p-c
400=100p-c
Solve:
100=20p
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3 0
3 years ago
Which relation is a function
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Top left

Step-by-step explanation:


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3 0
3 years ago
Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations. (-4, 9), (0,
Tresset [83]

Answer:

\boxed{y=2x^2+4x-7}

Step-by-step explanation:

Let the quadratic function be

y=ax^2+bx+c


We substitute (-4,9) into the equation to obtain;


9=a(-4)^2+b(-4)+c


\Rightarrow 9=16a-4b+c---(1)


We substitute (0,-7) to obtain;


-7=a(0)^2+b(0)^2+c


\Rightarrow c=-7---(2)


We finally substitute (1,-1) to obtain;


-1=a(1)^2+b(1)^2+c


\Rightarrow -1=a+b+c---(3)


We put equation (2) into equation (1) to get;


9=16a-4b-7


16a-4b=16


\Rightarrow 4a-b=4---(4)


\Rightarrow -1=a+b-7


\Rightarrow a+b=6---(5)


We add equation (4) and (5) to get;

4a+a=6+4



\Rightarrow 5a=10



\Rightarrow a=2


We put a=2 into equation (5) to get;


2+b=6


\Rightarrow b=6-2


\Rightarrow b=4


The reqiured quadratic function is

y=2x^2+4x-7

7 0
3 years ago
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