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AnnyKZ [126]
3 years ago
9

(08.03 LC) Factor completely: x2 + 10x + 24 (5 points) Prime (x + 12)(x + 2) (x + 3)(x + 8) (x + 6)(x + 4)

Mathematics
1 answer:
Alona [7]3 years ago
5 0

Answer:

Option C is correct

Step-by-step explanation:

We need to factorize the expression:

x^2+10x+24

For factorization we need to break the middle term such that the product is equal to 24x^2 and the sum is equal to 10x

We know that 6*4 = 24 and 6+4 =10

So, solving

=x^2+6x+4x+24

Taking common

=x(x+6)+4(x+6)

=(x+4)(x+6)

So, the factors of

x^2+10x+24

are

(x+4)(x+6)

Hence Option C is correct

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Each week, Abigail earns $75 for every shift she works at the pizzeria and $25 for every dog-walking job. She uses the expressio
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75x + 25y

Part A: coefficients = 75 & 25 variables = x & y

Part B: Terms = 2
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- term 2: 25y

Terms are the different parts or groups of an equation. Therefore, 75x is one term and the other is 25y. They are each a part of the equation. Without them you wouldn't have an equation at all.

Part C: Pizzeria pay = 75x because that is how much she makes each shift she works.

- Hope this helps. =)
4 0
3 years ago
Read 2 more answers
In a random sample of n1 = 162 males, there are x1 = 63 people that have blue eyes. In a random sample of n2 = 333 females, ther
sesenic [268]

Answer:

z = 2.1784 > 1.96,

Reject the null hypothesis

Step-by-step explanation:

For the males:

n1  = 162, x1 = 63

P1 = x 1/ n1 = 0.3889

For the Females:

n2 = 333,

x2 = 97

P 2 = x2/n2

= 0.2913

P 1= P2 Null hypothesis

P 1 is not equal to P 2 alternative hypothesis

Pooled proportion:

P= (x1 + x2) /( n1+ n2)

= (63 + 97) / (162 + 333)= 0.3232

Test statistics :

Z= (p1 - p2) /√p(1-p)× (1/n1 + 1/n2)

0.3889- 0.2913 / √0.3232 × 0.6768 × (1/162 +1/333)

=2.1784

c) Critical value :

Two tailed critical value, z critical = Norm.S .INV (0.05/2) = 1.960

Reject H o if z < -1.96 or if z > 1.96

d) Decision:

z = 2.1784 > 1.96,

Reject the null hypothesis

7 0
3 years ago
Peter attends 6 lessons each week . A year he attends 52 weeks. But he missed 5 classes how many lessons did he attend during th
VMariaS [17]
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He could potentially take 312 lessons in one year.

Now that you know this information, you simply subtract the days he missed from that total.

312 - 5 = 307

Your final answer: Peter took 307 lessons during the year.
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3 years ago
Sarah has 13 stickers. Sissy has 28 stickers. Sissy divides her stickers into 4 equal groups.
777dan777 [17]

Answer:

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Step-by-step explanation:

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