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yaroslaw [1]
3 years ago
6

Aden spent $10 on a mug and then sold it, making 20% profit. how much did he sell the mug for?

Mathematics
2 answers:
Aloiza [94]3 years ago
7 0
He sold it for $12 since 20% of 10 is 2
Sveta_85 [38]3 years ago
4 0

Answer:

12$

Step-by-step explanation:

10% of 10 is 1$ 20% of 10 is 2$ so the answer is 12$

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A number x plus 10 is more than 2
makvit [3.9K]
X+10>2. The simplified answer is x>-8
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3 years ago
What equation can I use to get 6 with the numbers 9,2,10,7,6
alekssr [168]

Answer:

10+2-6=6

Step-by-step explanation:

If you don’t need to use all the numbers,

10+2-6=6

7 0
3 years ago
PLEASE HELP PLEASE 9. A lake has an average depth of 4 feet. A new dam has just been completed, and the average depth of the lak
hoa [83]

Answer:

B

Step-by-step explanation:

I had the same question

6 0
2 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
Find the point slope equation of the line using the point (6,9) and slope of 3/2
Natali [406]

Answer:

y=1.5x

Step-by-step explanation:

Use the equation y-y1=m(x-x1)

y-9=1.5(x-6)

y-9=1.5x-9

y=1.5x

8 0
3 years ago
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