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Maslowich
4 years ago
10

A circle has a sector with area \dfrac{1}{2}\pi 2 1 ​ πstart fraction, 1, divided by, 2, end fraction, pi and central angle of \

purple{\dfrac{1}{9}\pi} 9 1 ​ πstart color #9d38bd, start fraction, 1, divided by, 9, end fraction, pi, end color #9d38bd radians . What is the area of the circle?
Mathematics
1 answer:
balu736 [363]4 years ago
8 0

Answer:

Area of circle = 9<em>π</em>

Step-by-step explanation:

Area of sector = \frac{1}{2} \pi

Its central angle = \frac{1}{9}\pi \text{ radians}

\text{Area of sector} = \dfrac{\text{Central angle}}{2\pi} \times\text{Area of circle}

\text{Area of circle} = \text{Area of sector}\times\dfrac{2\pi}{\text{Central angle}}

A = \dfrac{1}{2}\pi\times\dfrac{2\pi}{\frac{1}{9}\pi} = 9\pi

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Evaluate the expression
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x = - 3

Step-by-step explanation:

note that y = f(x)

locate y = 3 on the y- axis, go horizontally across to meet f(x) at (- 3, 3 ) , then

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Solve this equation 3(2x+3)=9
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Answer:

0

Step-by-step explanation:

Isolate the variable x. First, distribute 3 to all terms within the parenthesis.

3(2x + 3) = 3(2x) + 3(3) = 6x + 9

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Isolate the variable x. Note the equal sign, what you do to one side, you do to the other. First, subtract 9 from both sides.

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3 years ago
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I need this for myself. Help
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3 years ago
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Rewrite the expression $6j^2 - 4j 12$ in the form $c(j p)^2 q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$
solniwko [45]

Rewrite the expression  6j^2 - 4j + 12$ in the form $c(j + p)^2 + q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$

The ratio of \frac{q}{p}  = - 34

How to solve such questions?

Such Questions can be easily solved just by some Algebraic manipulations and simplifications. We just try to make our expression in the form which question asks us. This is the best method to solve such questions as it will definitely lead us to correct answers. One such method is completing the square method.

Completing the square is a method that is used for converting a quadratic expression of the form ax^{2} + bx + c to the vertex form

a(x - h)^{2} + k. The most common application of completing the square is in solving a quadratic equation. This can be done by rearranging the expression obtained after completing the square: a(x + m)^{2} + n, such that the left side is a perfect square trinomial

$6j^2 - 4j +12$

=  $6(j^2 - \frac{2}{3} j )+12$

= $6(j^2 - \frac{2}{3} j  +  \frac{1}{9}  )+\frac{102}{9}                   (Completing Square method)

=6( j- \frac{1}{3} )^{2}  +  \frac{34}{3}

On comparing with the given equation we get

p = - \frac{1}{3}     and q = \frac{34}{3}

∴ \frac{q}{p} = \frac{\frac{34}{3} }{\frac{-1}{3} }

= - 34

Learn more about completing the square method here :

brainly.com/question/26107616

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Can yall plz help me on this ???
Stolb23 [73]

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its the first one

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