Answer:
that conclude idk
Step-by-step explanation:
-6U+-15+3.5U=-1U
-2.5U+15
Cost of company A=monthlyfee+text=20+0.03t where t=number of texts
A=20+0.03t
company b is monthlyfee+texts=5+0.07t
B=5+0.07t
1.
c=20+0.03t
c=5+0.07t
using c for cost is confusing because we can't tell which is for which company
2.
equal, means the costs are equal so
20+0.03t=5+0.07t
minus 5 from both sides
15+0.03t=0.07t
minus 0.03t from both sides
15=0.04t
divide both sides by 0.04
375=t
the answer is 375 texts
Answer:
24 munchkins.
Step-by-step explanation:
Let C be the number of chocolate and D be number of glazed donut holes in the original box.
We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:
Upon substituting C's value from equation (2) in equation (1) we will get,
Let us have a common denominator on right side of equation.


Multiplying both sides of our equation by 7, we will get,

Multiplying both sides of our equation by 11, we will get,
Therefore, the total number of Munchkins in original box is 24.
Answer:
these are the step to follow so A=bh
Step-by-step explanation: A=1/2bh A=bh A=1/2 (b=b)h this is an example so you can follow how i did this
Answer:
3
Step-by-step explanation:
Usually, when there is contamination the smallest amount can have huge ramifications in the data collected. In this scenario, if in a "clean" environment the trait is found in 2/10 frogs then anything above this number should be considered contaminated. This is because data above this ratio would be considered uncommon or rare and this unique occurrence can be most likely tied to the only new factor which would be the contamination. Therefore the minimum number of frogs with this trait in the sample would be 3.