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olchik [2.2K]
3 years ago
8

What is the equation of the line that is perpendicular to the given line and passes through the point (2,6)

Mathematics
2 answers:
kobusy [5.1K]3 years ago
6 0

Answer:

x=2 is the equation of the line that is perpendicular to the given line and passes through the point (2,6).

Step-by-step explanation:

We are given a graph of line whose equation is y=-4 and passing point (-8,-4) and (8,-4).

We need to find the equation of line which is perpendicular to y=-4

As we know y=-4 is horizontal line on coordinate plane.

If a line perpendicular to y=-4 then it must be vertical line.

Equation of vertical line : x=h

Passing point of line (2,6)

x would be same for all points in vertical line.

Required equation of line: x=2

Thus, x=2 is the equation of the line that is perpendicular to the given line and passes through the point (2,6).

jeka943 years ago
5 0

Answer:

y=2

Step-by-step explanation:

hope this help...and is right!

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Step-by-step explanation:

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3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
2 years ago
Help on how to figure this out
MakcuM [25]
6/3 = 6 divided by 3
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12/6= 12 divided by 6
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3 0
3 years ago
Sean chewed 2/5 of his rawhide bones. If he had 10 bones to begin with, how many did he chew up?
Vesna [10]

Answer:

He chewed 4/10 of the bone

Step-by-step explanation:

Since the 10 will be the denominator you will need to divide it by 2 and get 5. After that you multiply the denominator of 10 and numerator of 1 by 2 and get 4/10

4 0
3 years ago
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