Question

The class of math is mapped on a coordinate grid with the origin been at the center point of the hall Mary's seat is located at the (2,2) and betty seat is located at (6,7) how far is Mary's seat to betty seat

Answer 1

Answer:

Marry's seat is $\sqrt{41}$ units far from Betty's seat

Step-by-step explanation:

We are given that Class of Math is mapped on a coordinate grid and center point of the hall is at origin.

Coordinates of Mary's seat are (2,2) and Coordinates of Betty's seat are (6,7). We have to find how far is Mary's seat to Betty's seat. In order words, we have to find the distance between Marry's seat and Betty's seat.

Remember that whenever the coordinates of two points are given, the distance between them is calculated using the distance formula. The distance between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given by distance formula as:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Here, the points with subscript 1 are initial points (2,2) and the point with subscript 2 are final points (6,7). Using these values in the formula, we get:

$d=\sqrt{(6-2)^{2}+(7-2)^{2}} \\\\ d=\sqrt{16+25}\\\\ d=\sqrt{41}$

This means, Marry's seats is $\sqrt{41}$ units far from Betty's seat