Answer:
गेइश स्ग्ग्ब्स अक्ग्क्स्हेइओदाब्द स्ज्श्ग।
Step-by-step explanation:
इतिहास स्कुलबाट फेरिएका स्थान ग्रामीण द्वन्द घ्यम्पो स्वास्थ फेरिएका ग्रामीण ह्याटि्रक वयो हजारमात्र अधि ह्यारी द्वन्द न्स्झ्ह अक्द्ग ज्स्ग्व्ब क्ज्ग्स व्हुदोक दिव्फ्क्स स्ज्फ्व्ब्व सुएब्स म्को इव द्क्व क्सिव्स द्ज्स न्व्क्व द्क्क स्न्कोब्स स्क्क्व्दुर् फ्ह्दुफ द्भ्फ फिद ज्द्क्क्न्फ व्व्द्ब्सिस सि द्कि द्ज्व्व द्ज्व्ह्कु श्व्ह्द ज अ स्स द्जि द ज्त्बिव व्बिक्ब।
Answer:
6 mins
Step-by-step explanation:
Given that;
T(t) = Ce^-kt + T(s)
Since T(t) = 200◦F, and T(s) = 70◦F where t = 0
200= Ce^-k(0) + 70
C= 200 - 70
C = 130
Then when T(t) = 190◦F and t= 1s ;
190 = 130e^-(k *1) + 70
190 - 70 = 130e-^(k *1)
120/130 = e^k
0.923 = e^-k
-k = ln(0.923)
k = 0.08
To determine the time taken to reach a temperature of 150◦F
150 = 130e^-(0.08t) + 70
150 - 70/130 = e^-(0.08t)
0.6154 = e^-(0.08t)
-(0.08t) = ln 0.6154
0.08t = 0.4855
t = 0.4855/0.08
t = 6 mins
Answer:
Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.
Step-by-step explanation:
By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.
Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.
By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.
Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625
y^2-y^2+0.5y+2.25–4.0625=0
0.5y- 1.8125=0
0.5y=1.8125
y=1.8125/0.5= 3.625
Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder
Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625
L^2=13.140625–0.90625+4.0615=15.390625
L= (15.390625)^1/2= 3.92 meters length of ladder
<em>hope it helps...</em>
<em>correct me if I'm wrong...</em>