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PilotLPTM [1.2K]
3 years ago
7

Simplifying rational expressions

Mathematics
1 answer:
garik1379 [7]3 years ago
4 0
(x+5)/(x+10) is the answer.
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Is 20 a prime or composite number.​
STALIN [3.7K]

Answer: It is a composite number since it has more factors than just itself and 1.

Step-by-step explanation:

1x20=20

2x10=20

4x5=20

6 0
3 years ago
Read 2 more answers
Gianna is going to throw a ball from the top floor of her middle school. When she throws the hall from 48 feet above the ground,
vazorg [7]

Answer:

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

Step-by-step explanation:

The height h of the ball is modeled by the following equation

h(t)=-16t^2+32t+48

The problem want you to find the times the ball will be 48 feet above the ground.

It is going to be when:

h(t) = 48

h(t)=-16t^{2}+32t+48

48=-16t^{2}+32t+48

0=-16t^{2}+32t+48 - 48

16t^{2} - 32t = 0

We can simplify by 16t. So

16t(t-2)= 0

It means that

16t = 0

t = 0

or

t - 2 = 0

t = 2

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

6 0
3 years ago
Help me?????? please
lutik1710 [3]
1. Match to B
2. Match to A
3. Match to D
4. Prime

Hope it helps!
4 0
3 years ago
Find the length of the hypotenuse in the right triangle below. 39in, 52in
Bingel [31]
If two sides of a right triangle are x and y, the hypotenuse, h is:

h^2=x^2+y^2, in this case x and y are 39 and 52 respectively so:

h^2=39^2+52^2

h^2=1521+2704

h^2=4225

h=√4225

h=65 in

So the hypotenuse is 65 inches.
3 0
3 years ago
Read 2 more answers
In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. The side lengths o
ycow [4]

Answer:

A

Step-by-step explanation:

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,

  • \angle CBD\cong \angle ACD\cong \angle CBA
  • \angle DCB\cong \angle DAC\cong \angle BAC

So,

\triangle ABC\sim \triangle CBD\sim \triangle ACD

1. From the similarity \triangle ABC\sim \triangle CBD, you have

\dfrac{AB}{BC}=\dfrac{BC}{BD}\\ \\\dfrac{c}{a}=\dfrac{a}{s}

2. From the similarity \triangle ABC\sim \triangle ACD, you have

\dfrac{AB}{AC}=\dfrac{AC}{AD}\\ \\\dfrac{c}{b}=\dfrac{b}{r}

Hence, option A is true

5 0
2 years ago
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