Answer:
4x+2
Step-by-step explanation:
(13x+x−53x)−(−43x+2)
Group all the same variables on each side.
(-39x)-(-43x+2)
-39x+43x+2
4x+2
Hope this helps :)
Square root of 289 = +17 and -17
Answer:
For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:
A = (1/2)*H*(X + Y)
with this we can complete the table.
a)
Here we know:
X = 7cm
Y = 11cm
H = 6cm
Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2
b)
Here we know:
X = 8 m
Y = 10 m
A = 126 m^2
Then:
126 m^2 = 0.5*H*(8m + 10m)
126 m^2 = H*9m
126 m^2/9m = H = 14m
Then the height of this trapezoid is 14m
c)
Here we know:
X = 5mm
H = 8mm
A = 72 mm^2
Then:
72 mm^2 = 0.5*8mm*(5mm + Y)
72 mm^2 = 4mm*(5mm + Y)
72mm^2/4mm = 5mm + Y
18 mm = 5mm + Y
18mm - 5mm = Y
13 mm = Y
Then the parallel side 2 is 13 mm long.
Answer is B 1, -1
y = -2x + 5
when x = 2; y = -2(2) + 5 = 1
when x = 3; y = -2(3) + 5 = -1
Answer:
Intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction
Step-by-step explanation:
Required vector is consists of the two components
vx= 2+4=6 units and vy= 1 unit and vx ⊥ vy
We will use Pythagorian theorem to find intensity of the vector v
v∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 units
The angle ∡α between vector and east direction we wil find with tanα
tanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°
Good luck!!!
