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lina2011 [118]
3 years ago
9

12meters; is how many FT

Mathematics
1 answer:
kkurt [141]3 years ago
4 0
12 meters is equal to 39.3701 feet.

1 meter is equal to 3.28084 feet.
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Mr. Nelson is buying property in the shape of a triangle to build a new house. If the property costs $42.50 per square foot, how
julsineya [31]
First, you find the area of the figure. Use the formula a=h(b/2)

a=h(b/2)
a=47(98/2)
a=47(49)
a=2303

Now, you multiply that by $42.50 to find out how much he will pay. 

2,303x42.50=97,877.50.

He will pay $97,877.50.
5 0
3 years ago
Read 2 more answers
A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

7 0
3 years ago
What is the slope and y intercept of y=3x+4
aev [14]
The slope is 3 and y-intercept is 4
y=mx+b
3 0
3 years ago
Read 2 more answers
Mrs.Jacinto asked carpenter to construct a rectangular bulletin board for her classroom. She told the Carpenter that the board's
Misha Larkins [42]

Answer:

6 ft by 3 ft

Step-by-step explanation:

3 0
3 years ago
What is the distance between (4,7) and (2,2)?
algol [13]
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 4}}\quad ,&{{ 7}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{(2-4)^2+(2-7)^2}\implies d=\sqrt{(-2)^2+(-5)^2}
\\\\\\
d=\sqrt{4+25}\implies d=\sqrt{29}
7 0
3 years ago
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