he solution set is
{
x
∣
x
>
1
}
.
Explanation
For each of these inequalities, there will be a set of
x
-values that make them true. For example, it's pretty clear that large values of
x
(like 1,000) work for both, and negative values (like -1,000) will not work for either.
Since we're asked to solve a "this OR that" pair of inequalities, what we'd like to know are all the
x
-values that will work for at least one of them. To do this, we solve both inequalities for
x
, and then overlap the two solution set
Answer:Option A is correct.
y-2=0
Step-by-step explanation:
Option A is correct.
General form of the equation of the line: y-2 = 0
Step-by-step explanation:
The general form of the equation is given by:
y = mx +b where m is the slope and b is the y-intercept.
y-intercepts of the line is the value of y at the point where the line crosses the y-axis(i.e x= 0)
From the given figure;
we can see that the line crosses the y-axis at y =2 and also here the slope is , m= 0
therefore, by definition of y-intercepts
y-intercept (b) = 2
Therefore, the equation of line as shoen in figure is:
y = (0)x + 2
or
y = 2
y-2 = 0
Therefore, the general form of the equation line as shown in the figure is:
y-2 =0
Hello,
f(x)=4(x+3)-5=4x+12-5=4x+7
y=4x+7==>c=(y-7)/4
f^(-1)(x)=(x-7)/4
f^(-1)( 3)=(3-7)/4=-4/4=-1
Answer D
*edit
Answer:
4/5
Step-by-step explanation:
you'd do 4 divided by 2 which is 2, then you'd do 10 divided by 2 which is 5. so you get 4/5.
9514 1404 393
Answer:
14.1 years
Step-by-step explanation:
Use the compound interest formula and solve for t. Logarithms are involved.
A = P(1 +r/n)^(nt)
amount when P is invested for t years at annual rate r compounded n times per year.
Using the given values, we have ...
13060 = 8800(1 +0.028/365)^(365t)
13060/8800 = (1 +0.028/365)^(365t) . . . . divide by P=8800
Now we take logarithms to make this a linear equation.
log(13060/8800) = (365t)log(1 +0.028/365)
Dividing by the coefficient of t gives us ...
t = log(13060/8800)/(365·log(1 +0.028/365)) ≈ 0.171461/0.0121598
t ≈ 14.1
It would take about 14.1 years for the value to reach $13,060.
