Answer:
See explaination
Explanation:
//Array to store prices
INT PRICE[10][10]
//Loop through 2d array
FOR I FROM 0 TO 10
FOR J FROM 0 TO 10
//Populate a random int
PRICE[I][J] = RANDOM_INT(99,1999)
PRINT(PRICE[I][J]+" ")
PRINT()
//Prompt user for desired price
COST = READ_INPUT('Please enter your desired flight price: ')
//Variable to store if a match is found
MATCH = FALSE
//Loop through all ints in price
FOR I FROM 0 TO 10
FOR J FROM 0 TO 10
//Compare price with Cost
IF PRICE[I][J]==COST
MATCH = TRUE
BREAK
//Check if match is true
IF MATCH = TRUE
PRINT('A flight was found for that price, have a safe trip!')
ELSE
PRINT('No flight was found for that price, please try a new price.')
Using a linear search to find a value that is stored in the last element of an array of 20,000 elements, 20,000 element(s) must be compared.
Answer:
a. count of observations that meet a condition (counts), total number of observations (nobs), Hypothesized value of population proportion (value).
Explanation:
In other to use the proportion_ztest method, the need to make import from the statsmodel module ; statsmodels.stats.proportion.proportions_ztest ; this will allow use use the Z test for proportion and once this method is called it will require the following arguments (count, nobs, value=None, alternative='two-sided', prop_var=False)
Where;
nobs = number of observations
count = number of successes in the nobs trial or the number of successes for each independent sample.
Value = hypothesized value of the population proportion.
+8 ounces ...don't know what an alrebra tile so I just subtracted :)
