If there are changes to the responsibilities in a career, the typical outcome will change.
Answer:
Yes it is possible for the following cases:-
- When the queue is full.
- When the queue is empty.
Explanation:
When the queue is full the the front and the rear references in the circular array implementation are equal because after inserting an element in the queue we increase the rear pointer.So when inserting the last element the rear pointer will be increased and it will become equal to front pointer.
When the queue is empty the front and rear pointer are equal.We remove an element from queue by deleting the element at front pointer decreasing the front pointer when there is only one element and we are deleting that element front and rear pointer will become equal after deleting that element.
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Answer:
Giving that: The following is a sequence of undo-log records written by 2 transactions T and U:
< START T >;
< T,A,10 >;
< START U >;
< U, B, 20 >;
< T, C, 30 >;
< U, D, 40 >;
< Commit U >;
< T, E, 50 >;
< Commit T >;
1. < START U >
Recovery action in this case will be undo(-1) and undo(0). All restored to its original Value
log records < T, A, 10 >, < T, abort >; as written out
2. < T, E, 50 >
Recovery action in this case will be undo(8) and redo(0). A and C is restored to its original value, B and D are set to 20 and 40
log records <T, C, 30 >, < T, A, 10 >, < T, abort > are written out
3. < Commit T >
Recovery action in this case will be redo(7) and redo(4). A and C are set to 10 and 30, B and D are set to 20 and 40
Answer: This is a python code
def lightyear():
rate=3*100000000 //speed of light
seconds=365*24*60*60 //number of seconds in 1 year
return str((rate*seconds)/1000)+" km" //distance=speed x time
print(lightyear()) //will print value of light hear in kilometers
OUTPUT :
9460800000000.0 km
Explanation:
In the above code, there is a variable rate, which stores the speed of light, i.e. distance traveled by light in 1 second which is in meters. Another variable is seconds, which store the number of seconds in 1 year, which is no of days in 1 year multiplied by the number of hours in a day multiplied by the number of minutes in an hour multiplied by the number of seconds in a minute. Finally, distance is speed multiplied by time, so distance is printed in kilometers and to convert distance in kilometers it is divided by 1000.
