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Alenkasestr [34]
3 years ago
15

3x +15 = 2x + 10 + x + 5

Mathematics
2 answers:
Nuetrik [128]3 years ago
7 0

Answer: x can equal any number

Step-by-step explanation:

3x + 15 = 2x + 10 + x + 5

First, combine the like terms on the right side

2x + x = 3x

10 + 5 = 15

3x + 15 = 3x + 15

Subtract 15 from both sides

3x = 3x

Divide each side by 3

x = x

This means that x can equal any number, and the equation will always be true.

Shkiper50 [21]3 years ago
4 0

Answer:

The equation is true.

Step-by-step explanation:

Simplify. Combine like terms:

3x + 15 = (2x + x) + (10 + 5)

3x + 15 = (3x) + 15

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract 3x and 15 from both sides:

3x (-3x) + 15 (-15) = 3x (-3x) + 15 (-15)

3x - 3x = 15 - 15

0 = 0

~ True. The two expressions are equal to each other.

~

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(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh
NemiM [27]

The final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

\sum_{i =1}^{n}x_{i}  follows an approximately normal distribution with a mean n\mu and standard deviation \sqrt{n }\sigma

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

Y = \sum_{i =1}^{10}x_{i}

Distribution of Y is normal with,

Mean = \mu _{y}=10*4 = 40 and standard deviation = \sigma _{y}=\sqrt{10}*0.75 = 2.3717

a)

P( Y < 42.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

=NORMDIST( x, mean, SD , 1 )      

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 )  = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

P( Y < 40.5 )  =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165  = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

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