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3 years ago

15

You work in a hospital,and instructions for an instrument state that it should be cleaned in the sterilizer for two hours. The s

terilizer requires cleaning time be entered in minutes. How many minutes do you set for the sterilizer?

1 answer:

icang [17]3 years ago

6 0

Answer:

120

Step-by-step explanation:

Due to an hour equaling 60 minutes, two hours would equal 120.

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ΔMNP is an isosceles triangle with MN ≈NP. If ∠ M = 3x + 1 and ∠ N = x - 11. What is the measure of ∠P?

denis23 [38]

I hope this helps you

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Calculate the average rate of change for the graphed sequence from n = 2 to n = 6.

ddd [48]

Answer:

-3

Step-by-step explanation:

The average rate of change from point (x1, y1) to point (x2, y2) is given by ...

m = (y2 -y1)/(x2 -x1)

For the given points, this is ...

m = (2 -14)/(6 -2) = -12/4 = -3

The average rate of change on the interval is -3.

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2 years ago

Please help with geometry homework!!!!

EleoNora [17]

Area of Parallelogram ABCD is equivalent to the area of rectangle AXBY.

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Thus Area of Parallelogram is 12√2 sq.ft.

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3 years ago

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valentina_108 [34]

Answer:

-4

Step-by-step explanation:

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2 years ago

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Use the chain rule calculate dw/dr , dw/ds and dw/dt

Liono4ka [1.6K]

Answer:

$\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ , $\frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ , $\frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$

Step-by-step explanation:

We proceed to derive each expression by rule of chain. Let be $w = \ln (x+2\cdot y + 3\cdot z)$ , $x = r^{2}+t^{2}$ , $y = s^{2}-t^{2}$ and $z = r^{2}+s^{2}$ :

$\frac{dw}{dr} = \frac{\frac{dx}{dr}+2\cdot \frac{dy}{dr} +3\cdot \frac{dz}{dr} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{dr} = 2\cdot r$

$\frac{dy}{dr} = 0$

$\frac{dz}{dr} = 2\cdot r$

$\frac{dw}{dr} = \frac{8\cdot r}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{dr} = \frac{8\cdot r}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (1)

$\frac{dw}{ds} = \frac{\frac{dx}{ds}+2\cdot \frac{dy}{ds} +3\cdot \frac{dz}{ds} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{ds} = 0$

$\frac{dy}{ds} = 2\cdot s$

$\frac{dz}{ds} = 2\cdot s$

$\frac{dw}{ds} = \frac{10\cdot s}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{ds} = \frac{10\cdot s}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (2)

$\frac{dw}{dt} = \frac{\frac{dx}{dt}+2\cdot \frac{dy}{dt} +3\cdot \frac{dz}{dt} }{x+2\cdot y + 3\cdot z}$

$\frac{dx}{dt} = 2\cdot t$

$\frac{dy}{dt} = -2\cdot t$

$\frac{dz}{dt} = 0$

$\frac{dw}{dt} = -\frac{2\cdot t}{(r^{2}+t^{2})+2\cdot (s^{2}-t^{2})+3\cdot (r^{2}+s^{2})}$

$\frac{dw}{dt} = -\frac{2\cdot t}{4\cdot r^{2}-t^{2}+5\cdot s^{2}}$ (3)

7 0

2 years ago