6. 24- factors:1&24,2&12,3&8, 4&6. 18 factors: 1&18, 2&9, 3&6. The highest number that can multiply into them is 6 so it is the GCF
Answer:
10
Step-by-step explanation:
the formula y = mx +c
the y is obviously, y.
m, also means the gradient has a value of -4
c is the y-intercept, so the value of c is 10.
<h3>Y
ou have the correct answer</h3><h3>Interest rate = 21.5%</h3>
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Work Shown:
i = P*r*t .... simple interest formula
i = simple interest
i = 2075-1000 = 1075
P = 1000 = amount borrowed (principal)
r = unknown interest rate
t = 5 = time in years
So,
i = P*r*t
1075 = 1000*r*5
1075 = 5000r
5000r = 1075
r = 1075/5000
r = 0.215
r = 21.5%
Answer:
(a) The expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.
(b) The probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.
Step-by-step explanation:
Let<em> </em>the random variable <em>X</em> be defined as the number of customers the salesperson assists before a customer makes a purchase.
The probability that a customer makes a purchase is, <em>p</em> = 0.52.
The random variable <em>X</em> follows a Geometric distribution since it describes the distribution of the number of trials before the first success.
The probability mass function of <em>X</em> is:

The expected value of a Geometric distribution is:

(a)
Compute the expected number of should a salesperson expect until she finds a customer that makes a purchase as follows:


This, the expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.
(b)
Compute the probability that a salesperson helps 3 customers until she finds the first person to make a purchase as follows:

Thus, the probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.
The answer can be readily calculated using a single variable, x:
Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%
The problem is then stated as:
(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000
Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.