The answer is 5.
Step-by-step explanation:
To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.
Answer:/
I,,,,M SORRYI NEED POINTSSS
Step-by-step explanation:
Answer:
(0,-5)
Step-by-step explanation:
3(4x+4y=20)
-3x-12y=-60
12x+12y=60
-3x-12y=-60
9x=0
x=0
4(0)+4y=-20
4y=-20
y=-5
Answer:
The correct answer is
(0.0128, 0.0532)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence interval 
, we have the following confidence interval of proportions.
In which
Z is the zscore that has a pvalue of 
For this problem, we have that:
In a random sample of 300 circuits, 10 are defective. This means that 
and 
Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.
So 
= 0.05, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The correct answer is
(0.0128, 0.0532)
Answer:
z= 2.38
P = 0.008656
Step-by-step explanation:
Here n= 500 and p~= 464/500= 0.928 and q`= 1- 0.928 = 0.072
We formulate our null and alternate hypothesis as
H0 = 0.9 ; H0 > 0.9
The degree of confidence = 90%
z₀.₀₅ = 1.645 for α= 0.05
We use the test statistic
z= x- np/√npq
z= 466-500 *0.9/ √500 * 0.9(1-0.9)
z= 466- 450/ √45
z= 16/6.7082
z= 2.38
As the calculated value of z= 2.38 is greater than α =1.645 so we reject H0.
If H0 is true the P value is calculated as
P = 1- Ф( 2.38)
P = 1-0.991344=0.008656
